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Mkey [24]
3 years ago
6

What are the center and radius f the circle with equation xthe power of 2 +y power of 2 -4x -6y +8=0

Mathematics
1 answer:
Dovator [93]3 years ago
6 0
<span>x² +y² -4x -6y +8=0
(x² -4x) +(y² -6y) = -8
We are going to complete square for x and y,
it should look like a²+2ab+b² = (a +b)², or </span>a²-2ab+b² = (a -b)²,
<span>
(x²-2*2x+2²) -2² + (y²-2*3y +3²)-3²=- 8
(x-2)²+(y-3)²-4-9=-8
</span>(x-2)²+(y-3)²=-8+13
(x-2)²+(y-3)²=5
<span>
Formula a circle (x-h)²+(y-k)²=R², where vertex has coordinates (h, k) 

So , for our circle  vertex (2,3) and radius = </span>√5<span>


</span>
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A)

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x*2x + x*2 + 2*2x + 2*2 = 110

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2x² +6x - 106 = 0

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b² - 4ac = 6² - 4*2*(-106)

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x =\dfrac{-b+\sqrt{b^{2}-4ac}}{2a} \ ; \ x==\dfrac{-b-\sqrt{b^{2}-4ac}}{2a}\\\\x = \dfrac{-6+29.73}{2*2} \ ; \ x =\dfrac{-6-29.73}{2*2} \ this \ is \  ignored \ as \ it \ is \  negative\\\\x=\dfrac{23.73}{4};

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3 years ago
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mr_godi [17]

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p/s: do your teachers teach you how to use ∆ ( delta ) in maths calculation ? i live in europe and our teachers teach us that way. however, it is a rịght and fast way. you should learn it.

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