= 1455
generate a few terms of the sequence using = 3n + 2
= ( 3 × 1) + 2 = 5
= (3 × 2) + 2 = 8
= (3 × 3 ) + 2 = 11
= (3 × 4 ) + 2 = 14
= ( 3 × 5 ) + 2 = 17
the terms are 5, 8, 11, 14, 17
these are the terms of an arithmetic sequence
sum to n terms is calculated using =
[ 2a + (n-1)d]
where a is the first term and d the common difference
d = 8 - 5 = 11 - 8 = 14 - 11 = 3 and = 5
=
[( 2 × 5) + (29 × 3) ]
= 15( 10 + 87) = 15 × 97 = 1455
Answer:
8. Louis
9. Rose; Raymond
Step-by-step explanation:
8. An exponent represents the number of times the base appears as a factor in the product.
We use a coefficient to signify repeated addition: 3x means x+x+x.
We use an exponent to signify repeated multiplication. x³ means x·x·x.
So, the expression ...
You can see that the factor 4 appears 7 times in the product, so would be represented in exponential form as ...
Louis has correctly observed this fact. In general, we see that multiplying powers of the same base causes those powers to be added.
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9.
<u>Part A</u>. Rose is correct for the same reason as in problem 8.
5^5 · 5^2 = 5^(5+2) = 5^7
<u>Part B</u>. Raymond is correct. We know that division cancels similar terms from the numerator, so ...
__
The rules of exponents we're using here are ...
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
La fracción 11/20 no puede ser una fracción mixta ya que es una fracción propia es decir el numerador es menor al denominador.
Digamos que si usaramos el recíproco de la fracción si se podría pasar a mixta ya que en ese caso seria impropia.
Solo las fracciones impropias pueden ser mixtas.
Por ejemplo si invertimos la fracción :
Así que no la fracción 11/20 no puede ser una fracción mixta.
#Spj1