All categories

3 years ago

Find the value of x and the value of y

Mathematics

1 answer:

erik [133]3 years ago

5 0

The triangle is an isosceles triangle with exactly two congruent angles.
Since the two 45-deg angles are congruent, their opposite sides are also congruent. That makes y = 5.

This triangle is a 45-45-90 triangle. In a 45-45-90 triangle, the legs are congruent and the hypotenuse is sqrt(2) times the length of the legs.
The hypotenuse has length x, so x = 5 * sqrt(2) = 5sqrt(2)

Answer: B. x = 5sqrt(2), y = 5

You might be interested in

What is equivalent to (x+1) (x-2)(x+4)(3x+7)

marta [7]

Answer: 6x*9

Step-by-step explanation:

open parathesises to

x+1*x-3*x+4*3x+7

combine like terms

6x*9

you can’t simplify further so bam

hope i did this right and it helps :)

8 0

3 years ago

What is the value for the missing angle ??

allsm [11]

Answer: 9 inches.
Do the pythagorean theorem to find your answer.
Formula: a^2 + b^2 = c2
12 = b
15 = c
a^2 + 12^2 = 15^2
Simplify the equation
a^2 + 144 = 225
Subtract 144 on both sides.
a^2 = 81
Square root of 81 is 9.

8 0

2 years ago

How do you simplify 8x over 45

Hitman42 [59]

x over 5 becuase the top and bottom are both divisible by 8 so you do that.

3 0

3 years ago

Read 2 more answers

Find the 40th term of the arithmetic sequence-2,1,4,7,10

klio [65]

A40=a1 +(40-1)r
in this case r is 3 beceause -2+3 will be 1 etc
a40=-2 +39*3

3 0

3 years ago

Read 2 more answers

Show all work and reasoning

Natalija [7]

Split up the interval [2, 5] into $n$ equally spaced subintervals, then consider the value of $f(x)$ at the right endpoint of each subinterval.

The length of the interval is $5-2=3$ , so the length of each subinterval would be $\dfrac3n$ . This means the first rectangle's height would be taken to be $x^2$ when $x=2+\dfrac3n$ , so that the height is $\left(2+\dfrac3n\right)^2$ , and its base would have length $\dfrac{3k}n$ . So the area under $x^2$ over the first subinterval is $\left(2+\dfrac3n\right)^2\dfrac3n$ .

Continuing in this fashion, the area under $x^2$ over the $k$ th subinterval is approximated by $\left(2+\dfrac{3k}n\right)^2\dfrac{3k}n$ , and so the Riemann approximation to the definite integral is

$\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n$

and its value is given exactly by taking $n\to\infty$ . So the answer is D (and the value of the integral is exactly 39).

8 0

3 years ago