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Nat2105 [25]
2 years ago
12

Find the value of x and the value of y

Mathematics
1 answer:
erik [133]2 years ago
5 0
The triangle is an isosceles triangle with exactly two congruent angles.
Since the two 45-deg angles are congruent, their opposite sides are also congruent. That makes y = 5.

This triangle is a 45-45-90 triangle. In a 45-45-90 triangle, the legs are congruent and the hypotenuse is sqrt(2) times the length of the legs.
The hypotenuse has length x, so x = 5 * sqrt(2) = 5sqrt(2)

Answer: B. x = 5sqrt(2), y = 5
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Multiply.
Elena-2011 [213]

Answer:

5/1.6 -2.5=<u>0.625</u>

3 0
2 years ago
Read 2 more answers
Write an equation of the line in slope-intercept form for the graph<br><br> Please helppp
Anvisha [2.4K]

Answer:

y=-4/3+2

Step-by-step explanation:

Sin the slope is going up to the left we can already infer that it is going to be a negative. Still we do the equation y2-y1/x2-x1. In this case 0 is x1 and 2 is y1, 3 is x2, and -2 is y2. Once inserted into the equation you get -2-2/3-0 which equals -4/3 and the y intercept is 2 since thats the point shown were it intercepts the y-axis

8 0
2 years ago
Please help!!! How many coefficients does this polynomial have in its complete form, including any missing terms?
frez [133]
-5x^3 + 2x^2 + 1

a coefficient is the number that is multiplied by the variable.For instance, the coefficient of 2x is 2....because 2 (the number) is multiplied by the variable x.

so in ur problem....there are 2 coefficients..-5 and 2.

** the number 1 is not a coefficient, it is a constant...a " loner " with no variables (letters) attached.

** and if u have just the letter...such as n, the coefficient to that is 1 but the one is just not written...it is actually 1n.

okay...I am gonna shut up now :) 
7 0
2 years ago
I feel so stupid, but I need helping figuring out this problem. I can’t remember how to do it. Can someone help me please
AleksandrR [38]
The answer is C. 
90/105=6/7
Hope this helps!
3 0
2 years ago
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)

7 0
1 year ago
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