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svetoff [14.1K]
3 years ago
15

The geometric sequence a_ia i ​ a, start subscript, i, end subscript is defined by the formula: a_1 = -\dfrac13a 1 ​ =− 3 1 ​ a,

start subscript, 1, end subscript, equals, minus, start fraction, 1, divided by, 3, end fraction a_i = a_{i - 1} \cdot (-3)a i ​ =a i−1 ​ ⋅(−3)a, start subscript, i, end subscript, equals, a, start subscript, i, minus, 1, end subscript, dot, left parenthesis, minus, 3, right parenthesis Find the sum of the first 757575 terms in the sequence.
Mathematics
1 answer:
slava [35]3 years ago
5 0

Answer:

1.014*10^35

Step-by-step explanation:

Given the following geometric sequence

a_1 = \frac{-1}{3} \\a_i = a_{i-1}*(-3)

Sum of nth term of the GP is expressed as;

S_n = \frac{a(1-r^n)}{1-r}

a = -1/3

n = 75

r = a2/a1

a2 = -3a1

a2 = -3(-1/3)

a2 = 1

r = 1/(-1/3)

r = -3

Substitute the given values in the formula;

S_n = \frac{-1/3(3^{75} - 1)}{3-1}\\S_n = \frac{3^{75}-1}{-6} \\S_{75} = 1.014*10^{35}

Hence the sum of the first 75 terms is 1.014*10^35

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find three consecutive integers for which 3 times the sum of the first and third integers is -342? show step by step
Artyom0805 [142]

Answer:

-58, -57, -56

Step-by-step explanation:

if the first integer is x,

the second integer must be x + 1 (because it's consecutive)

and the third must be x + 2

Therefore:

3 times the sum of the first and third integers is -342:

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Combine like terms in parentheses

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Divide by 6 on both sides

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x + 1 = -57

x + 2 = -56

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Check:

3 * (-58 + -56) = 3 * -114 = -342

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