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balandron [24]
3 years ago
15

Factorise fully 6x^2 + 12x

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

6x(x+2)

Step-by-step explanation:

Factor 6x out of 6x^2+12x

6x(x+2)

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JulijaS [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Find the area between the graph of the function and the x-axis over the given interval, if possible.
vodomira [7]

Answer:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

Step-by-step explanation:

In order to calculate the area between the function and the x axis we need to solve the following integral:

A = \int_{-\infty}^1 \frac{5}{(x-2)^2}

For this case we can use the following substitution u = x-2 and we have dx = du

A = \int_{a}^b \frac{5}{u^2} du = 5\int_{a}^b u^{-2}du

And if we solve the integral we got:

A= -\frac{5}{u} \Big|_a^b

And we can rewrite the expression again in terms of x and we got:

A = -\frac{5}{x-2} \Big|_{-\infty}^1

And we can solve this using the fundamental theorem of calculus like this:

A= -\frac{5}{-1} - \lim_{x\to\infty} \frac{5}{x-2} = 5-0 = 5

So then the integral converges and the area below the curve and the x axis would be 5.

7 0
3 years ago
(x - 6) (X - 4) =<br> How do I solve this?
Vedmedyk [2.9K]

Answer: x^2 -10x + 24

Step-by-step explanation:

(x-6) (x-4)

= x^2 - 6x - 4x + 24

= x^2 -10x + 24

5 0
3 years ago
Read 2 more answers
Which of these strategies would eliminate a variable in the system of equations?
gtnhenbr [62]

Answer:

option A

Step-by-step explanation:

8 0
3 years ago
Determine whether or not the relation is a function. Please help asap
OLga [1]

Answer:

A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function

Step-by-step explanation:

4 0
2 years ago
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