Step-by-step explanation:
tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)
= (sin2B + cos2B)/[(cosB)(sinB)]
= 1/[(cosB)(sinB)]
= (1/cosB)(1/sinB)
= (secB)(cscB)
Answer:
x = 18 y = 10
Step-by-step explanation:
let the first number be x
let the second number be y
x = y + 8..... equation 1
2x + y = 46.... equation 2
x is the larger number
y is the smaller number.
Rearrange the equation and add equation 1 to equation 2.
x - y = 8
+ 2x + y = 46
-------------------
3x + 0 = 54
3x = 54
divide both sides by 3
x = 54/3
x = 18
Substitute x = 18 into equation 1
x = y + 8
18 = y + 8
collect like terms
y = 18-8
y = 10
I don't because I can't see