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ser-zykov [4K]
2 years ago
10

Please show how you got your answer to the problem. 4/5 + 3/15 - 2/3 =

Mathematics
1 answer:
natta225 [31]2 years ago
5 0

Answer:

Simplified Answer: 1/3 Non-Simplified Answer: 5/15

Step-by-step explanation:

Make every fraction have a common denominator:

4/5 * 3/3 = 12/15

3/15 = 3/15

2/3 * 5/5 = 10/15

Add and/or Subtract the numerator(s):

12 + 3 = 15

15 - 10 = 5

Place the final numerator over the denominator (Non-simplified Answer):

5/15

Simplify (What can you divide the numerator and the denominator by to make the fraction into it's simplest from without any remainders?):

5 goes into both 5 and 15.

5/15 divided by 5 = 1/3

Simplified Answer:

1/3

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Draw a histogram for the intervals 16-18,19-21, 22-24, and 25-27 using the following data: 26, 16, 27
Kitty [74]

Answer with explanation:

Class Interval             Variate         Frequency

16-18                              16                     1

19-21                               0                     0

22-24                               0                    0

25-27                              26,27              2

8 0
3 years ago
The are of a rectangle is 259cm2 and its length is 18.5 cm .Find its breath
Hoochie [10]

Answer:

A=L×B

259=18.5×B

295=18.5B

295/18.5=18.5B/18.5

8.595=B

5 0
3 years ago
Help me with this question
Llana [10]

The answer is B

(3^4*abc^-7)^6=(3^4*6)(a^6)(b^6)(c^6*-7)=(3^24*a^6*b^6)/(b^42)

6 0
2 years ago
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
3 years ago
Fine the solution of 4x^2+4x+1=0
Natalka [10]

Answer:

x = -1/2

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
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