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1 answer:
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Answer:
0.1575 m/s^2
Explanation:
Solution:-
- Acceleration ( a ) is expressed as the rate of change of velocity ( v ).
- We are given that the trains starts from rest i.e the initial velocity ( vo ) is equal to 0. Then the train travels from reference point ( so = 0 ) to ( sf = 5.6 km ) from the reference.
- During the travel the train accelerated uniformly to a speed of ( vf =42 m/s ).
- We will employ the use of 3rd kinematic equation of motion valid for constant acceleration ( a ) as follows:
- We will plug in the given parameters in the equation of motion given above:
Answer: the acceleration during the first 5.6 km of travel is 0.1575 m / s^2
In order to find out if the exponential function represents a growth or a decay, let's look at the number that is base to the exponent x.
If the number is greater than 1, so the function represents a growth, and if the number is less than 1, the function represents a decay.
Since the number is 1.075, the function represents a growth.
To find the % increase, first let's convert the number to percentage, and then subtract 100%:
So the percent increase is 7.5%.