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Allisa [31]
2 years ago
14

All of the waves in the electromagnetic spectrum are _______ waves.

Physics
2 answers:
user100 [1]2 years ago
5 0
Transverse, I think. I may be wrong.
zimovet [89]2 years ago
3 0
The answer is Transverse.

I hope this helps. :)
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A Gaussian surface in the form of a hemisphere of radius R = 3.04 cm lies in a uniform electric field of magnitude E = 1.64 N/C.
Likurg_2 [28]

Answer:

Part a)

\phi = -4.76 \times 10^{-3} Nm^2/C

Part b)

\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C

Explanation:

Part a)

Electric flux entering into the base

so it is given as

\phi = E.A

\phi = - EA

\phi = -(1.64)(\pi r^2)

\phi = -(1.64)(\pi\times 0.0304^2)

\phi = -4.76 \times 10^{-3} Nm^2/C

Part b)

Now since we know that there is no enclosed charge in the hemisphere

so net flux must be zero

\phi_{curved} + \phi_{flat} = 0

\phi_{curved} - 4.76 \times 10^{-3} = 0

\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C

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1d. Conservation of energy is demonstrated in this roller coaster example.
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Answer:

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An object is five focal lengths from a concave mirror.how do the object and image heights compare?
enot [183]

An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable <span>(s’) represents the distance between the mirror surface and the image. </span>

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

M= 5f/4x5f

s’ = 1/4s

Therefore, the image height is one fourth of the object height

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