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3 years ago

All of the waves in the electromagnetic spectrum are _______ waves.

Physics

2 answers:

user100 [1]3 years ago

5 0

Transverse, I think. I may be wrong.

zimovet [89]3 years ago

3 0

The answer is Transverse.

I hope this helps. :)

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A biker to move from speed of 0 m/s to final speed of 25 m/s in 10 s. What is the acceleration of the bike?

Rzqust [24]

Answer:

a = 2.5 m/s²

Explanation:

given,

initial speed = 0 m/s

final speed = 25 m/s

time = 10 s

acceleration of bike is equal to change in velocity per unit time

$a = \dfrac{\Delta v}{t}$

$a = \dfrac{v_f-v_i}{t}$

$a = \dfrac{25-0}{10}$

a = 2.5 m/s²

hence, acceleration of bike is equal to a = 2.5 m/s²

4 0

3 years ago

The amplitude of a sound is the A. frequency of the sound. B. magnitude of displacement of a sound pressure wave. C. psychologic

AlladinOne [14]

Answer:

Option B. magnitude of displacement of a sound pressure wave

Explanation:

Amplitude is simply the maximum displacement of a wave from its mean position.

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4 years ago

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Two objects move toward each other because of gravitational attraction. As the objects get closer and closer, the force between

bearhunter [10]

<span>Two objects move toward each other because of gravitational attraction. As the objects get closer and closer, the force between them increases. </span>

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3 years ago

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Water flows at 0.850 m/s from a hot water heater, through a 450-kPa pressure regulator. The pressure in the pipe supplying an up

grin007 [14]

Answer:

The velocity is $v_2= 0.45 \ m/s$

Explanation:

From the question we are told that

The initial speed of the hot water is $v_1 = 0.85 \ m/s$

The pressure from the heater $P_1 = 450 \ KPa = 450 *10^{3} \ Pa$

The height of the hot water before flowing is $h_1 = 0 \ m$

The height of bathtub above the heater is $h_2 = 3.70 \ m$

The pressure in the pipe is $P_2 = 414 KPa = 414 *10^{3} \ Pa$

The density of water is $\rho = 1000 \ kg/m^3$

Apply Bernoulli equation

$P_1 + \rho gh_1 +\frac{1}{2} \rho v_1^2 = \rho g h_2 + \frac{1}{2}\rho v_2 ^2$

Substituting values

$(450 *10^{3}) + (1000 * 9.8 * 0) + (0.5 * 1000 * 0.85^2) = (1000 * *9.8*3.70) + (0.5*1000*v_2^2 )$

=> $v_2^2 = \frac{ (450 *10^{3}) + (1000 * 9.8 *0 ) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}$

=> $v_2= \sqrt{ \frac{ (450 *10^{3}) + (1000 * 9.8 * 0) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}}$

=> $v_2= 0.45 \ m/s$

4 0

3 years ago

What is the role of the mid ocean ridge in the movement of lithosphere?

azamat

Magma can be let out of the lithosphere to form new crust and old crust can be absorbed into the lithosphere.

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4 years ago