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crimeas [40]
3 years ago
14

Which bulbs would be on and or off if :

Physics
2 answers:
insens350 [35]3 years ago
6 0
Bulbs c and b would still be screwed in if they were in to begin with and bulbs A, D, and E. would be unscrewed
Alex73 [517]3 years ago
6 0
-- If Bulb-A is removed or burns out . . .
ON:  B,  D,  E
OFF:  A,  C

-- If Bulb-D is removed or burns out . . .
ON:  A,  C,  E
OFF:  B,  D 

-- If Bulb-E is removed or burns out . . .
ON:  none 
OFF:  all
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Calculate the radius of each ball to the nearest tenth. Use the formula r = d/2 where r is the radius and d is the diameter. Rec
erma4kov [3.2K]

Answer:

What is the radius of the table tennis ball?

 ⇒ 2.1 cm  

What is the radius of the golf ball?

2.0  cm

Explanation:

divide the radius and round it to the nearest 10th place..... but hope that help ;)

8 0
3 years ago
Read 2 more answers
A 4.80 −kg ball is dropped from a height of 15.0 m above one end of a uniform bar that pivots at its center. The bar has mass 7.
Margarita [4]

Answer:

h = 13.3 m

Explanation:

Given:-

- The mass of ball, mb = 4.80 kg

- The mass of bar, ml = 7.0 kg

- The height from which ball dropped, H = 15.0 m

- The length of bar, L = 6.0 m

- The mass at other end of bar, mo = 5.10 kg

Find:-

The dropped ball sticks to the bar after the collision.How high will the other ball go after the collision?

Solution:-

- Consider the three masses ( 2 balls and bar ) as a system. There are no extra unbalanced forces acting on this system. We can isolate the system and apply the principle of conservation of angular momentum. The axis at the center of the bar:

- The angular momentum for ball dropped before collision ( M1 ):

                                 M1 = mb*vb*(L/2)

Where, vb is the speed of the ball on impact:

- The speed of the ball at the point of collision can be determined by using the principle of conservation of energy:

                                  ΔP.E = ΔK.E

                                  mb*g*H = 0.5*mb*vb^2

                                  vb = √2*g*H

                                  vb = ( 2*9.81*15 ) ^0.5

                                  vb = 17.15517 m/s

- The angular momentum of system before collision is:

                                  M1 = ( 4.80 ) * ( 17.15517 ) * ( 6/2)

                                  M1 = 247.034448 kgm^2 /s

- After collision, the momentum is transferred to the other ball. The momentum after collision is:

                                  M2 = mo*vo*(L/2)

- From principle of conservation of angular momentum the initial and final angular momentum remains the same.

                                 M1 = M2

                                 vo = 247.03448 / (5.10*3)

                                 vo = 16.14604 m/s

- The speed of the other ball after collision is (vo), the maximum height can be determined by using the principle of conservation of energy:

                                  ΔP.E = ΔK.E

                                  mo*g*h = 0.5*mo*vo^2

                                  h = vo^2 / 2*g

                                  h = 16.14604^2 / 2*(9.81)

                                  h = 13.3 m

3 0
3 years ago
If a ball is thrown vertically upward with a velocity of 80 ft/s, then its height after t seconds is s = 80t − 16t 2 . (a) what
MAXImum [283]
Max height occurs when v = 0.
v(t) = ds(t)/dt
v(t) = 80 - 32t
0 = 80 - 32t
t = 5/2

s(5/2) = 80(5/2) - 16(5/2)^2
s(5/2) = 100
Answer: 100 ft

96 = 80t - 16t²
t = 3, 2
(80 ± √256) / 32 using the quadratic equation.

v(2) = 16
v(3) = -16
4 0
2 years ago
Answer fast , is si unit newton/meter square or pascal or both
Readme [11.4K]

Answer:

Both

Explanation:

The S.I. unit of pressure is newton/meter square or pascal as both represent the same dimensional value.

8 0
2 years ago
Explain Bernoulli's Principle, air pressure, Down Wash, Angle of Attack, and vortices simply.
lord [1]

just listen I am also confused in this question if you get the answer so please just tell me also

3 0
3 years ago
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