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zlopas [31]
3 years ago
11

How does the asthenosphere interact with the tectonic plates at a divergent boundary?

Chemistry
2 answers:
DaniilM [7]3 years ago
6 0

Answer:

Its D

Explanation:

miskamm [114]3 years ago
5 0

Answer: what do u mean

Explanation:

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Describe a physical change and a chemical change that an iron nail could undergo.
galina1969 [7]
Physical change

iron nail have high melting point, thus, when it is heated, it will not melt very easily.

chemical change

iron nail can rust due to the exposure to the air(oxygen). iron in the nail and oxygen in the air will react together to form iron oxide(rust).
furthermore, the reaction is irreversible.
8 0
3 years ago
If 78.4 grams of aluminum metal react with excess hydrochloric acid, how many grams of hydrogen gas can be produced?2al + 6hcl y
qaws [65]
Answer is: 8,7g.
Chemical reaction: 2Al + 6HCl → 2AlCl₃ + 3H₂.
m(Al) = 78,4g.
n(Al) = m(Al)÷M(Al) = 78,4g ÷ 27g/mol = 2,9 mol.
n - amount of substance.
from reaction: n(Al) : n(H₂) = 2 : 3.
2,9mol : n(H₂) = 2 : 3.
n(H₂) = 4,35 mol.
m(H₂) = n(H₂)·M(H₂) = 4,35mol · 2g/mol = 8,7g.
6 0
3 years ago
What is another term for the limbic system?:
disa [49]

Answer:

a

Explanation:

because the sytem it si locate at the bothe side

7 0
3 years ago
Read 2 more answers
WILL GIVE 90 POINTS !!!
Lyrx [107]

Answer:

Answer is: A. Vinegar and soda.

Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH)  and a base (in this example soda or some other base) react quantitatively with each other.

Balanced chemical reaction of vinegar and soda:

CH₃COOH(aq) + Na⁺(aq) → CH₃COONa(aq) + H⁺(aq).

Sodium acetate (CH₃COONa) is a salt.

3 0
3 years ago
Read 2 more answers
odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add
Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

Explanation :

First we have to calculate the moles of H_2SO_4.

\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}

Given:

Molar mass of H_2SO_4 = 98 g/mole

Mass of H_2SO_4 = 6.05\times 10^3kg=6.05\times 10^6g

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol

The moles of H_2SO_4 is, 6.17\times 10^4mol

Now we have to calculate the moles of Na_2CO_3

The balanced neutralization reaction is:

Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3

From the balanced chemical reaction we conclude that,

As, 1 mole of H_2SO_4 neutralizes 1 mole of Na_2CO_3

So, 6.17\times 10^4mol of H_2SO_4 neutralizes

Now we have to calculate the mass of Na_2CO_3

\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3

Molar mass of Na_2CO_3 = 106 g/mole

\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg

Thus, the mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

3 0
4 years ago
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