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1 year ago

What displays the number of atoms, nature and bond types in organic compounds

Chemistry

1 answer:

alexgriva [62]1 year ago

5 0

Answer:

Structural formula

Explanation:

Various type of formulae describe an organic compound. The empirical formula only shows the ratio of atoms of each element present. The molecular formula shows the exact number of atoms of each element present.

Lastly, the structural formula shows us the arrangement of these atoms in space. It shows us the number of atoms, nature and bond types in organic compounds.

The structural formula enables us to picture what the real molecule must look like.

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2 years ago

An air compressor draws in 1,200 cf of free air at a gauge pressure of 0 psi and a temperature of 70°F. The air is compressed to

lubasha [3.4K]

Answer:

The final volume of air after compression: V₂ = 4477.63 L = 158.12 cf

Explanation:

Given: Initial gauge pressure of the gas = 0 psi

Initial absolute pressure of the gas: P₁ = gauge pressure + atmospheric pressure = 0 psi + 12.20 psi = 12.20 psi

Initial Temperature = 70°F

⇒ T₁ = (70°F − 32) × 5/9 + 273.15 = 294.26 K

Initial volume of the gas: V₁ = 1200 cf = 1200 × 28.317 = 33980.4 L (∵ 1 cf ≈ 28.317 L)

Final gauge pressure of the gas = 90 psi

Final absolute pressure of the gas: P₂ = gauge pressure + atmospheric pressure = 90 psi + 12.20 psi = 102.2 psi

Final Temperature: T₂ = 125°F

⇒ T₂ = (125°F − 32) × 5/9 + 273.15 = 324.82 K

Final volume of the gas: V₂ = ? L

According to the Combined gas law:

$\frac{P_{1}\times V_{1}}{T_{1}} = \frac{P_{2}\times V_{2}}{T_{2}}$

→ $V_{2} = \frac{P_{1}\times V_{1}\times T_{2}}{T_{1}\times P_{2}}$

→ $V_{2} = \frac{12.20 psi\times 33980.4 L\times 324.82 K}{294.26 K\times 102.2 psi}$

→ $V_{2} = 4477.63 L = 158.12 cf$

Therefore, the final volume of air after compression: V₂ = 4477.63 L = 158.12 cf

7 0

2 years ago

What displays the number of atoms, nature and bond types in organic compounds​

What displays the number of atoms, nature and bond types in organic compounds