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3 years ago

-6(x-3) pls help me....

Mathematics

2 answers:

yan [13]3 years ago

8 0

Answer:

18 - 6x

Step-by-step explanation:

According to the distributive property:

-6(x-3) =

-6*x + -6*-3 =

-6x + 18

MariettaO [177]3 years ago

4 0

Answer:

−6x+18

Step-by-step explanation:

-6(x-3)

(−6)(x+−3)

=(−6)(x)+(−6)(−3)

=−6x+18

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3 years ago

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2 years ago

a bicycle wheel has a diameter of 65cm what is the length of one revolution of the wheel PLEASE HELP

Lana71 [14]

AnswerAnswerAnswerAnswer: C = πd = 65π = 204.2 cm

Step-by-step explanation: C = pi*d

where d is the diameter.

First we get the circumference, then we multiply it by the number of revolutions, which is 20:

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2 years ago

Read 2 more answers

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$