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Vinvika [58]
3 years ago
15

Please help me with these two problems I need help

Mathematics
1 answer:
sweet [91]3 years ago
7 0

Answer:

24 area

18.80983669  perimeter

Step-by-step explanation:

1  (6*3/2)*2(1*3/2)+(4*3)

2 trust me

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Can you please help me answer this​
lesya692 [45]

9514 1404 393

Answer:

  (a)  Not congruent

Step-by-step explanation:

Angles are congruent, which means the triangles are <em>similar</em>. We need to know at least one pair of corresponding sides is congruent in order to say the triangles are congruent. No sides are marked, so we must conclude ...

  Not Congruent

8 0
3 years ago
Susan has purchased a whole life policy with a death benefit of $200,000. Assuming that she dies in 10 years and the average inf
Anika [276]

Answer:

Answer is: $148,809.52

Step-by-step explanation:

Susan has purchased a whole life policy with a death benefit of $200,000.

Assuming that she dies in 10 years.

Rate = 3% or 0.03

Future value after 10 years = (1+r)^{n} = (1.03)^{10} = 1.344

Purchasing power of proceeds = \frac{200000}{1.344}= $148,809.52

5 0
3 years ago
Graph the function: y=x-5​
ANEK [815]

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
marta [7]

Answer:

(a) The probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b) <em>n</em> = 28.09

Step-by-step explanation:

The random variable <em>Y</em>ₙ is defined as the total numbers of dollars paid in <em>n</em> years.

It is provided that <em>Y</em>ₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of <em>Y</em>ₙ are:

\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}

(a)

For <em>n</em> = 20 the mean and standard deviation of <em>Y</em>₂₀ are:

\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\

Compute the probability that <em>Y</em>₂₀ exceeds 1000 as follows:

P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z>  4.47)\\=1-P(Z

**Use a <em>z </em>table for probability.

Thus, the probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b)

It is provided that P (<em>Y</em>ₙ > 1000) > 0.99.

P(Y_{n}>1000)=0.99\\1-P(Y_{n}

The value of <em>z</em> for which P (Z < z) = 0.01 is 2.33.

Compute the value of <em>n</em> as follows:

z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n}  \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0

The last equation is a quadratic equation.

The roots of a quadratic equation are:

n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of <em>n</em> = 28.09.

8 0
3 years ago
What is the surface area of the triangular prism shown? A triangular prism. The triangle faces have base 14 meters and height 24
Alekssandra [29.7K]

Answer:

1064 m²

Step-by-step explanation:

The surface area of the prism can be gotten by saying

14 * 14 + 14 * 14 + 14 * 24 =

196 + 196 + 336 =

728 m²

Again, after dealing with the rectangle, we then face the triangle.

Area of triangle is

1/2 * 14 * 24

There are 2 triangles so this makes it

2 * 1/2 * 14 * 24 =

336

The surface area is finally

336 + 728 = 1064 m²

Surface area of the triangular prism has been calculated to be 1064 m²

3 0
3 years ago
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