15 1/3 - 6 1/4 - 4 2/3 = <span>4.41666666667 hours</span>
Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.
For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.
<h3>Binomial probability distribution
</h3>
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- One in ten students are named Joe, hence
.
- There are 15 students in the class, hence
.
The probability that at least one of them is named Joe is:

In which:


Then:

0.7941 = 79.41% probability that at least one of them is named Joe.
To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377
Answer:
The answer is D.) 6/8 and 3/4
Step-by-step explanation:
If you count how many lines there are you get 8 lines so we know the denominator has to be eight and since the point is on the 6th line the first one is 6/8 and since you can simplify it you get 3/4 which gives you D.)
Hope I helped
A brainliest is always appreciated
Answer:
so you can simplify the ratio
Step-by-step explanation:
Answer:
(-14)+(-8)
Step-by-step explanation: