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Irina18 [472]
3 years ago
7

Find a linear equation in your life?

Mathematics
2 answers:
Crank3 years ago
5 0

My life is not linear. Time is not constant. My life (and time included) is just a series of times that do not run parallel to each other. Instead, they drift further or closer as a function of velocity and curvature of space time.

Lena [83]3 years ago
3 0

Answer: If you are looking for a linear equation in your life, an example could be the rate of the grass growing in your lawn. The y axis could be the height and the x axis could be the time. As it grows, the line representing the grass could go up gradually; when you cut it, the line can stop. Keep doing that for however long you'd like to represent the grass growing/getting cut.

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How to write 8/15 as a decimal?
Murrr4er [49]

Answer:

0.53

Step-by-step explanation:

Basically just go to your calculator and put in 8 divded by 15

3 0
3 years ago
If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm
Juliette [100K]
<span>A midpoint divides a line or a segment into two equal parts. If D is the midpoint of the segment AC and C is the midpoint of segment DB, what is the length of the segment AB, if AC = 3 cm.</span>

 

If D is the midpoint of AC, then AD=DC

If C is the midpoint of DB, then DC=CB

If AC=3cm. then then DC-3/2=1.5

If DC=1.5 then CB is 1.5 also

AB=AC+CB

AB=3+1.5

AB=4.5

5 0
3 years ago
You deposit $3000 in an account earning 4% interest compounded continuously. How much will you have in
V125BC [204]

Answer: $3,664.21

Formula: A=Pe^{rt}

  • P = principle/original amount = $3000
  • r = rate of interest = 4% = 0.04
  • t = time period (in years) = 5
  • A = the new amount
  • e = Euler's number ≈ 2.718...

Substitute in the values:

A=(3000)e^{(0.04)(5)} =(3000)e^{0.2} =(3000)(1.2214)=3664.208

<u>Approximately $3,664.21</u>

<em>I think this is how you solve it o_O</em>

7 0
3 years ago
At the bottom of this page, the footnote explains the social security tax rate for 2011. How much was it for a self-employed ind
Alex17521 [72]
Look at the bottom of the page, the answer is there. At least that's what the question says.
6 0
4 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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