The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
5
Step-by-step explanation:
(4+11)/3 = 15/3 = 5
Answer:
4536363646
Step-by-step explanation:
Answer:
-6 = x
Step-by-step explanation:
2x-8=4(x+1)
Distribute
2x -8 = 4x+4
Subtract 2x
2x-8-2x = 4x-2x+4
-8 = 2x+4
Subtract 4
-8-4 = 2x+4-4
-12 = 2x
Divide by 2
-12/2 = 2x/2
-6 = x
Y - y1 = m(x - x1)
slope(m) = -3
(2,-1)...x1 = 2 and y1 = -1
now we sub....pay attention to ur signs
y - (-1) = -3(x - 2)....not done yet
y + 1 = -3(x - 2) <===
