Question

Graph the line of the equation 5x+2y=12 using its slope and y-intercept.

Answer 1

Answer:

Step-by-step explanation:

First you need to put the equation in slope intercept form.

y = mx + b   (m = slope and b = y-intercept)

5x + 2y = 12   (subtract 5x)

2y = -5x + 12   (now you need to isolate y. Therefore, divide all by 2)

y = -5/2x + 6

Now you have your slope and y-intercept. Your y-intercept will be 6. So on the graph you need to begin at 6 on the y-axis (the line that goes up and down). Make your first point there. Your slope is the -5/2x. Slope is looked at as rise/run. This means from your point at 6, you will go down (down because it's negative. If it was a positive, you would go up, i.e rise) 5 units. Then you will go over to the right 2 units (to the right because it is positive. Only the top one will be negative.) Place your point once you have done that. Then draw a line between those two points.

(note that on my screenshot, the tiny squares do not equal 1 unit. The larger ones with the bunch of tiny squares inside equal 1 unit)

I hope this helped :)