Answer:
The sample proportion from the sample of 900 is more likely to be close to the true population proportion, p.
Step-by-step explanation:
for the first one
Answer:
Thank you!!!
Step-by-step explanation:
Answer: 0.332 < p < 0.490
Step-by-step explanation:
We know that the confidence interval for population proportion is given by :-
, where n= sample size
= sample proportion
z* = critical z-value.
As per given , we have
n= 258
Sample proportion of college students who own a car =
Critical z-value for 99% confidence interval is 2.576. (By z-table)
Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be :
Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490
Answer:
(d) -11
Step-by-step explanation:
Each of the functions is evaluated in the usual way: put the number where the variable is in the expression and simplify.
h(-1) = -2(-1)² -3(-1) +1 = -2 +3 +1 = 2
f(2) = (2(2) +7)/(2 -3) = 11/-1 = -11
Then f(h(-1)) is ...
f(h(-1)) = f(2) = -11
20% Is the correct answer for the question