Question

Compute the sum of all integers that are multiples of 9, from 1 to 250. Enter your result of your computation in the text box below

Answer 1

The pseudocode to find the sum of all integers that are multiples of 9, from 1 to 250.

totalSum = 0

for i from 1 to 250{

     if i is divided by 9 and remainder is 0{

           totalSum  = totalSum + i;

     }

}

print(totalSum)

in python language the code will be

totalSum = 0

for i in range(1,250):

    if i%9==0:

       totalSum += i

If you will run the program , the answer would be 3402.

Answer 2

Answer:

To find the sum of all integers that are multiples of 9 from 1 to 250, first initialize the total sum with zero (0). After this, define for loop from 1 to 250 so that all the integers from 1 to 250 will be checked. Now, define the condition if the number is divisible by 9 or not. If number is divisible by 9 then add the integer with total sum. This process continues till the number 250. Thus, the total sum is the sum of the multiples of 9 from 1 to 250.

Further Explanation:

Following is the python program to calculate sum of the multiples of 9 from 1 to 250.

Code:

sum = 0

for i in range(1,250):

if i%9==0:

sum = sum+ i

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Answer details:

• Grade: Middle School
• Subject: Computers and Technology
• Chapter: Python Programming

Keywords:

Python, JAVA, C++, C, compute, sum, all integers, multiples of 9, from 1 to 250, result, text box, below, sum, range