Answer:
see explanation
Step-by-step explanation:
given
f'(x) = 12cos x - 4sin x, then
f'(
) = 12cos(
) - 4sin(
)
[ cos(
) = -cos(
), sin(
= - sin(
) ]
= -12cos(
) + 4sin(
)
= - 12 ×
+ 4 × ![\frac{\sqrt{3} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%7D)
= - 6 + 2
≈ - 2.536 ( 3 dec. places )
Answer:
51%.
Step-by-step explanation:
If we have that the probability when at least one wins is 0.3, it means that the probability that none wins would be:
1 - 0.3 = 0.7 would be the probability of not winning any of the first two games, how are two games and are independent events, the probability of not winning any of the 4 games would be:
(0.7) * (0.7) = 0.49
Therefore, the probability of winning at least one game, would be the complement of not winning any, that is:
1 - 0.49 = 0.51
Which means that the probability of winning at least 1 of the four game is 51%.
<span>
Answer: PQ=5, QR=radical 61= 7.81, angle: 50degrees,</span>Why:PQ=|-3|+2=5PR=6<span>angle Alfa, so there is right angle triangle PQR so I can use following formula:</span>PQ^2 + RP^2=QR^2;25 + 36=QR^2;QR=radical 61<span>also I can use: sinus (angle)=PR/QR;</span><span>sin(angle)=6/radical61=0.76822 which gives angle to be little bit more than 50 degrees{sinus 50 degrees=<span>0,7660</span>}. </span>
Answer:
4(x+2) / 5(x-1)
Step-by-step explanation:
We have given two expressions.
2x / x-1 expression I
5x / 2x+4 expression II
we have to find the quotient of expression I and expression II.
(2x / x-1 ) ÷ (5x / 2x+4)
Applying following rule:
a ÷ b = a× 1/b
(2x/x-1)×( 2x+4 / 5x)
(2x)(2x+4) / (x-1)(5x)
(2)(2)(x+2) / (x-1)(5)
4(x+2) / 5(x-1) which is the answer of given question.