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3 years ago

CORRECT ANSWER GETS BRAINLIEST!!! (∩^o^)⊃━☆

Physics

2 answers:

mr Goodwill [35]3 years ago

5 0

Answer:

GIVE THE PERSON ABOVE BRAINLIEST UwU

Explanation:

Volgvan3 years ago

3 0

Answer:

C. Wedge

Explanation:

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A home uses ten 100-watt lightbulbs for five hours per day. Approximately how many kilowatt-hours of electrical energy are consu

timurjin [86]

The electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

The given parameters:

Number of light bulbs = 10
Power consumed by each bulb = 100 W
Time of energy consumption, t = 1 year

<h3>What is electrical energy?</h3>

This is the electric power consumed or dissipated at a given period of time.

The electrical energy consumed in one year by using the light bulbs is calculated as

E = Pt

$E = (100 \times 10) \times (1 \ yr \times \frac{8760 \ hrs}{1 \ yr} )= 8,760,000 \ W att-hours\\\\
E = \frac{8,760,000 }{1000} = 8,760 \ kWh$

Thus, the electrical energy consumed in one year by using the light bulbs is 8,760 kWh.

Learn more about electrical energy here: brainly.com/question/60890

4 0

2 years ago

A student has begun training for tryouts for cross country by running a two mile loop through

Nataliya [291]

Answer:cause they running down a steep hill

Explanation: that's a confusing question

6 0

3 years ago

Exoplanets (planets outside our solar system) are an active area of modern research. Suppose astronomers find such a planet that

Leno4ka [110]

Answer:

8.829 m/s²

Explanation:

M = Mass of Earth

m = Mass of Exoplanet

$g_e$ = Acceleration due to gravity on Earth = 9.81 m/s²

g = Acceleration due to gravity on Exoplanet

$m=M-0.1M\\\Rightarrow m=0.9M$

$g_e=G\frac{M}{r^2}$

$g=G\frac{0.9M}{r^2}$

Dividing the equations we get

$\frac{g}{g_e}=\frac{G\frac{0.9M}{r^2}}{G\frac{M}{r^2}}\\\Rightarrow \frac{g}{g_e}=0.9\\\Rightarrow g=0.9g_e\\\Rightarrow g=0.9\times 9.81\\\Rightarrow g=8.829\ m/s^2$

Acceleration due to gravity on the surface of the Exoplanet is 8.829 m/s²

3 0

4 years ago

The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands

Ghella [55]

Answer:

Pressure on both feet will be $500N/m^2$

Explanation:

Weight of the person F = 500 N

Area of foot print $A=0.5m^2$

Area of both the foot $A=2\times 0.5=1m^2$

We have to find pressure on both the feet

Pressure is equal to ratio of force and area

So pressure $P=\frac{F}{A}$

$P=\frac{500}{1}=500N/m^2$

So the pressure on both feet will be $500N/m^2$ when person stands on both feet.

7 0

4 years ago

A current of 2.35 A flows through a 1.11 mm diameter copper wire that is connected to a capacitor plate. The current is directed

antoniya [11.8K]

Answer:

charge flowing in the copper wire is $2.585\times 10^{-3}C$

Explanation:

We have given current i = 2.35 A

Time through which charge is charge is transferred $t=1.10\times 10^{-3}sec$

We have to find the charge flowing in this time

We know that charge is given by Q = i×t , here i is current and t is time

So charge = $Q=1.1\times 10^{-3}\times 2.35=2.585\times 10^{-3}C$

So charge flowing in the copper wire is $2.585\times 10^{-3}C$

6 0

4 years ago