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Pani-rosa [81]
4 years ago
11

A current of 2.35 A flows through a 1.11 mm diameter copper wire that is connected to a capacitor plate. The current is directed

toward the plate. Find the charge transferred to the plate in 1.10 x 10^-3 s.
Physics
1 answer:
antoniya [11.8K]4 years ago
6 0

Answer:

charge flowing in the copper wire is 2.585\times 10^{-3}C

Explanation:

We have given current i = 2.35 A

Time through which charge is charge is transferred t=1.10\times 10^{-3}sec

We have to find the charge flowing in this time

We know that charge is given by Q = i×t , here i is current and t is time

So charge = Q=1.1\times 10^{-3}\times 2.35=2.585\times 10^{-3}C

So charge flowing in the copper wire is 2.585\times 10^{-3}C

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<em>Answer:</em>

<h2><em>6</em><em> </em><em>m/</em><em>s</em></h2>

<em>solution \\ distance \: travelled = 1.8 \: km \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  1.8 \times 1000m \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 1800 \: m \\ time \: taken = 5 \: minute \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 5 \times 60 \: seconds \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 300 \: seconds \\ average \: velocity =  \frac{distance \: travelled}{time \: taken}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{1800}{ 300}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 6 \:  {ms}^{ - 1}</em>

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