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Pani-rosa [81]
4 years ago
11

A current of 2.35 A flows through a 1.11 mm diameter copper wire that is connected to a capacitor plate. The current is directed

toward the plate. Find the charge transferred to the plate in 1.10 x 10^-3 s.
Physics
1 answer:
antoniya [11.8K]4 years ago
6 0

Answer:

charge flowing in the copper wire is 2.585\times 10^{-3}C

Explanation:

We have given current i = 2.35 A

Time through which charge is charge is transferred t=1.10\times 10^{-3}sec

We have to find the charge flowing in this time

We know that charge is given by Q = i×t , here i is current and t is time

So charge = Q=1.1\times 10^{-3}\times 2.35=2.585\times 10^{-3}C

So charge flowing in the copper wire is 2.585\times 10^{-3}C

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The rate at which bus 1 is going is 55 mph

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Suppose, the distance traveled by Bus 1 be 'd' at the rate R after a time, t = 3h

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3 years ago
22. What is the length of a pendulum that has a period of 0.500 s?
sergeinik [125]

6.21 cm

  • use the pendulum formula : \sf \bold{\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}}

where

  • T is time or period
  • π is pie = 22/7
  • L is pendulum length
  • g is acceleration due to gravity

Given:

  • T = 0.500 s
  • g = 9.8 m/s²

solving step-wise:

\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}

\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}

\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}

\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }

\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2

\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8

\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m

  • 1 m → 100 cm

\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm

\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm             { rounded to nearest hundredth }

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