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Pani-rosa [81]
3 years ago
11

A current of 2.35 A flows through a 1.11 mm diameter copper wire that is connected to a capacitor plate. The current is directed

toward the plate. Find the charge transferred to the plate in 1.10 x 10^-3 s.
Physics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

charge flowing in the copper wire is 2.585\times 10^{-3}C

Explanation:

We have given current i = 2.35 A

Time through which charge is charge is transferred t=1.10\times 10^{-3}sec

We have to find the charge flowing in this time

We know that charge is given by Q = i×t , here i is current and t is time

So charge = Q=1.1\times 10^{-3}\times 2.35=2.585\times 10^{-3}C

So charge flowing in the copper wire is 2.585\times 10^{-3}C

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3 years ago
Why do the magnetic forces acting on the coil change as the current running through the coil changes?
VladimirAG [237]

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What is the name of the device that regulates the amount of fuel going into the engine of a personal watercraft (pwc)?
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3 years ago
A solid conducting sphere with radius R carries a positive total charge Q. The sphere is surrounded by an insulating shell with
Illusion [34]

Answer:

Explanation:

Volume of the insulating shell is,

V_{shell}=\frac{4}{3}\pi(R^3_2-R^3_1)

Charge density of the shell is,

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi(R^3_2-R^3_1)}

Here, R_2 =2R, R_1 =R \,and\, Q_{shell} =-Q

\rho=\frac{Q_{shell}}{\frac{4}{3}\pi((2R)^3-R^3)}=\frac{-3Q}{28\piR^3}

B)

The electric field is E=\frac{1}{4\pi\epsilon_0}\frac{Qr}{R^3}

For 0 <r<R the electric field is zero, because the electric field inside the conductor is zero.

C)

For R <r <2R According to gauss law

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substitute \rho=\frac{-3Q}{28\piR^3}

E=\frac{2}{7\pi\epsilon_0}\frac{Q}{r^2}-\frac{Qr}{28\piR^3}

D)

The net charge enclosed for each r in this range is positive and the electric field is outward

E)

For r>2R

Charge enclosed is zero, so electric field is zero

8 0
3 years ago
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