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Alex Ar [27]
4 years ago
12

The three forces (in units of N) given below are acting on a 20 kg mass. Calculate the magnitude of the acceleration of the mass

. stack F subscript 1 with rightwards harpoon with barb upwards on top equals 3 i with hat on top space space space space space stack F subscript 2 with rightwards harpoon with barb upwards on top equals 5 j with hat on top space space space space stack F subscript 3 with rightwards harpoon with barb upwards on top equals open parentheses i with hat on top minus 3 j with hat on top close parentheses space space
Physics
1 answer:
Mrrafil [7]4 years ago
8 0

Answer:

Acceleration, a=0.223\ m/s^2

Explanation:

Mass of the object, m = 20 kg

The forces acting on the objects are as follows :

F_1=3i

F_2=5j

F_3=i-3j

The net force acting on the object is, F=4i+2j

Let a is the acceleration of the mass. It can be calculated using the second law of motion as :

F=ma

a=\dfrac{F}{m}

a=\dfrac{4i+2j}{20}

a=\dfrac{1}{5}i+\dfrac{1}{10}j

|a|=\sqrt{(\dfrac{1}{5})^2+(\dfrac{1}{10})^2}

a=0.223\ m/s^2

So, the magnitude of the acceleration of the mass is 0.223\ m/s^2. Hence, this is the required solution.

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