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3 years ago

A student reads at a rate of 16 pages per day which ordered pair would be in a graph of this relationship

Mathematics

2 answers:

True [87]3 years ago

7 0

(1,16), (2,32), (3,48) etc...

PolarNik [594]3 years ago

3 0

(1,16),(2,32),(3,48) etc...

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The probability, P, that a person responds to an advertisement can be modeled by the exponential function P = 1 – e^-0.047t. In

Ray Of Light [21]

Answer:

c. 60.9%

Step-by-step explanation:

Given:

The probability P that a person responds to an advertisement can be modeled by the function:

$P=1-e^{-0.047t}$

where $t$ represents number of days since the advertisement first appeared.

To find the probability that a person has responded after 20 days.

Solution:

In order to find the probability that a person has responded after 20 days, we will plugin $t=20$ in the formula given.

We have:

$P(t)=1-e^{-0.047t}$

Plugging in $t=20$

$P(20)=1-e^{-0.047(20)}$

$P=1-e^{-0.94}$

$P=1-e^{-0.047t}$

$P=1-0.3906$

$P=0.6094$

Thus, probability $P$ after 20 days = 0.6094

The probability in percentage can be given = $0.6094\times 100$ = 60.9%

7 0

3 years ago

Double bubble/ triple 100 points !!!!!!

balu736 [363]

Answer:

see below

Step-by-step explanation:

We need to find the diameter of the square

We can find this using the Pythagorean theorem

a^2+b^2 = c^2 where the legs are 7 and 7 and the diameter is c

7^2 +7^2 = c^2

49+49 = c^2

98 = c^2

Taking the square root of each side

sqrt(98) = sqrt(c^2)

9.899494937 = c

Since 9.9 is less than 11 which is the diameter of the circle it will never touch the circle.

Since the longest part of the square is less than the diameter of the circle, the square will fit inside the circle without touching

3 0

3 years ago

Read 2 more answers

Let f be a continuous function defined on the interval [0,1] such that f(0) = f(1). Show that there exists a number 0 <= a &l

Leni [432]

Explanation:

In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula $g(x) = f(x+1/2)-f(x) .$

If we evaluate g at the endpoints we have

g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))

g(1/2) = f(1) - f(1/2) = -g(0)

Since g(1/2) = -g(0), we have one chance out of three

g(0) > 0 and g(1/2) < 0
g(0) < 0 and g(1/2) > 0
g(0) = g(1/2) = 0

We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0. This proves that g has at least one zero on [0,1/2].

Let c be a 0 of g, then we have

$0 = g(c) = f(c+1/2)-f(c)$