Question

Joes Enough income has been increasing each year by the same dollar meal the first year his income was $22,000 in the fourth year his income was $24,100 in which year was his income 33,900

Answer 1

Answer:

In the 23rd  year his income was of $33,900.

Step-by-step explanation:

Joe's income has been increasing each year by the same dollar amount.

This means that his salary after t years is given by:

$S(t) = S(0) + at$

In which S(0) is the initial salary and a is the yearly increase.

The first year his income was $22,000

This means that $S(0) = 22000$. So

$S(t) = S(0) + at$

$S(t) = 22000 + at$

In the fourth year his income was $24,100

S(4) = 24100, and thus, we use this to find a.

$S(t) = 22000 + at$

$24100 = 22000 + 4a$

$4a = 2100$

$a = \frac{2100}{4}$

$a = 525$

So

$S(t) = 22000 + 525t$

In which year was his income 33,900

This is t for which S(t) = 33900. So

$S(t) = 22000 + 525t$

$33900 = 22000 + 525t$

$525t = 11900$

$t = \frac{11900}{525}$

$t = 22.67$

Rounding up, in the 23rd year his income was of $33,900.