Question

Assume the random variable X is normally distributed with mean μ=50 and standard deviation σ=7. Find the 81st percentile.

Answer 1

Answer:

$P(81)=56.16$

Step-by-step explanation:

From the question we are told that:

Mean $\mu=50$

Standard Deviation $\sigma=7$

Percentile 81st

Generally Probability of 81st Percentile

 $P(Z$

Using Standard normal Table

 $P(Z$

Therefore the 81st percentile is given as

 $P(81)=z*\sigma *\mu$

 $P(81)=0.88*7*50$

 $P(81)=56.16$