Answer:
b
Step-by-step explanation:
100 dollars month
100
plus
100+
0.15 per text
100+15t
Answer:
The number of pounds of cashew is 11
Step-by-step explanation:
Let P represent the peanut
Let C represent the cashew nut.
From question, we were told that Elijah brought a total of 16 pounds of peanuts and cashew nuts. This can be written as:
P + C = 16 (1)
The total cost = $49.50
Cost per peanut = $2.75
Cost per cashew = $3.25
The above can be represented as:
49.50 = 2.75P + 3.25C. (2)
From equation 1,
P + C = 16
P = 16 — C
Substitute the value of P into equation 2:
49.50 = 2.75P + 3.25C.
49.50 = 2.75(16 — C) + 3.25C
49.50 = 44 — 2.75C + 3.25C
49.50 = 44 + 0.5C
Collect like terms
49.50 — 44 = 0.5C
5.5 = 0.5C
Divide both side by 0.5
C = 5.5/0.5
C = 11
Therefore, the number of pounds of cashew is 11
Answer:
B
Step-by-step explanation:
Also solved eveything
(x+9)^2=49
x^2+18x+81=49
x^2+18x+32=0
a=1, b=18 and c=32
x= (-18 +/- Sqrt (18^2-4×32))/2
x= (-18 +/- Sqrt (324-128))/2
x= (-18 +/- Sqrt (196))/2
x= (-18 +/- 14)/2
x= (-18 +14)/2 = -4/2 =-2
OR
x= (-18 -14)/2 = -32/2 =-16
We can round 5.65 up to 6 and 3.4 down to 3.
3 * 6 = 18
now let's see how close our estimate is to the real answer
5.65 * 3.4 = 19.21
Our answer was pretty close to the real answer!
Hope I helped!
~ Zoe
THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION