Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable
int num;
int tot_sum=0;
cout<<"enter a number: ";
// read the value of n
cin>>num;
// check the multiple of 2 or 5 from 1 to n
for(int x=1;x<=num;x++)
{
// if multiple of 2 or 5 then add them
if(x%2==0 ||x%5==0)
{
tot_sum=tot_sum+x;
}
}
// print the sum
cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;
return 0;
}
Explanation:
Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.
Output:
enter a number:11
sum of multiple of 2 or 5 is:35
They use multiple techniques to help children.
Pretty sure its called the grooming process
Question options:
a. RAID 0
b. RAID 1
c. RAID 5
d. RAID 6
e. RAID 10
Answer:
d. RAID 6
Explanation:
RAID is Redundant Array of Inexpensive/Independent Disks. RAID combines low cost physical hard disk drives in one hard disk drive. RAID is used to achieve data redundancy(data backup but with synchronization) or improved performance or both.
To get what the director requires he would need to use RAID 6. RAID 6 is RAID level optimized to achieve data redundancy but with slow performance.
send attached file with it
