We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
Side JL is 4√2 recall that in a 30-60-90 right triangle the hypotenuse is 2 times the size of the short leg.
JL also serves as the hypotenuse of the 45-45-90 triangle JML. The ratio of side lengths in this triangle is 1:1:√2
So we can see that the value of x = 4
B. four million eighty-four thousand and nine hundred four thousandths
Answer:
Step-by-step explanation:
3.14(pi) X 6 ^2 =
3.14*6 = 18.84
3.14x6^2 =36
your final answer is : B. : 36