Answer:
The magnitude of the acceleration of the elevator is 0.422 m/s²
Explanation:
Lets explain how to solve the problem
Due to Newton's Law ∑ Forces in direction of motion is equal to mass
multiplied by the acceleration
We have here two forces 460 N in direction of motion and the weight
of the person in opposite direction of motion
The weight of the person is his mass multiplied by the acceleration of
gravity
→ W = mg , where m is the mass and g is the acceleration of gravity
→ m = 45 kg and g = 9.8 m/s²
Substitute these values in the rule above
→ W = 45 × 9.8 = 441 N
The scale reads 460 N
→ F = 460 N , W = 441 N , m = 45 kg
→ F - W = ma
→ 460 - 441 = 45 a
→ 19 = 45 a
Divide both sides by 45
→ a = 0.422 m/s²
<em>The magnitude of the acceleration of the elevator is 0.422 m/s²</em>
Answer:
Magnitude of gravitational force of the electron= 3.74×10^12N
Explanation:
Felectron= Fgravitational
Therefore:
Felectron/Fgravitational = kq^2/r^2 ×(r^2/Gm^2)
= kq^2/Gm^2
Where G= gravitational constant
m = mass of electron=9.1×10^-31
K= 8.9x10^9
q= 1.6×10^-19
Magnitude of gravitational force= (8.9×10^9)×(1.6×10^-19)^2/(6.7×10^-11)×(9.1×10^-31)
=( 2.2784×10^-28) / ( 6.097×10^-41)
= 3.74×10^12N
Answer:
A closest
Explanation:
This is because the electric field will be strongest or largestwhen the equipotential curves are closest together
We know that the field is
E= V/d
Where is distance and we see that d being the denominator will only make E bigger if it becomes smaller that is the curves closest
<em> Frequency is perceived by humans as pitch; The sound intensity is the amplitude; Humans can only hear a specific range of sound, usually from 20 Hz to 20,000 Hz; The factors that go into a sound are its intensity, frequency and overtones (which are like interference, or background noises).</em>
Answer:
39.375 A
Explanation:
To find the induced current, we use the relation
e = -ΔΦ/Δt, where
ΔΦ = change in magnetic flux of the bracelet
Δt = change in time, = 20 ms
Also, Φ = A.ΔB, such that
A = area of the bracelet, 0.005m²
ΔB = magnetic field strength of the bracelet = 1.35 - 4.5 = -3.15 T
ΔΦ = A.ΔB
ΔΦ = 0.005 * -3.15
ΔΦ = -.01575 wb
e = -ΔΦ/Δt
e = -0.01575 / 20*10^-3
e = 0.7875 V
From the question, the resistance of the bracelet is 0.02 ohm, so
From Ohms Law, I = V/R
I = 0.7875 / 0.02
I = 39.375 A
