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Alenkasestr [34]
3 years ago
8

The weight of a body of certain mass become zero in space.Why?​

Physics
2 answers:
Natali [406]3 years ago
5 0

Answer:

there is no gravity

Explanation:

konstantin123 [22]3 years ago
4 0
[Weight of a body depends upon mass and acceleration due to gravity (since w=m*g). Mass is constant quantity but acceleration due to gravity is variable.] space is a null point where value of acceleration due to gravity is zero hence weight becomes zero.
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A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it w
choli [55]

The equation relevant to this is:

S(t) = So + Vot - At²/2 <span>

</span>

<span>Therefore we can create two equations:
<span>S(t) = 90 = So - 4t - 16.1t²                                      --> eqtn  1</span>
<span>S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)²                     --> eqtn 2</span>

</span>

<span>Expanding eqtn 2:
10 = So - 4t - 8 - 16.1(t² + 4t + 4) 
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4 
10 + 8 + 64.4 = So - 68.4t - 16.1t² 
<span>82.4 = So - 68.4t - 16.1t²                                        --> eqtn 3</span></span>

 <span>
Subtracting eqtn 1 by eqtn 3:</span>

 90 = So - 4t - 16.1t² 

82.4 = So - 68.4t - 16.1t²

 

=> 7.6 = 64.4t

t = 0.118 s

 

Therefore calculating for initial height So:<span>

<span>82.4 = So - 68.4(0.118) - 16.1(0.118)²

<span>So = 90.7 ft</span></span></span>

7 0
3 years ago
Answers please!! i have to give it up in 2 hours!!
aleksklad [387]

Answer:

this isn't physics this is german

3 0
4 years ago
The universe could be considered an isolated system because
Stolb23 [73]

Answer:

A(many people think that no energy or matter exists outside the universe)

Explanation:

4 0
3 years ago
2. Write five honest ways of earning money.?​
dimaraw [331]

Answer:

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8 0
3 years ago
Read 2 more answers
Each shot of the laser gun favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the dis
Alisiya [41]

Answer:

a) 4.94e9 J  b) 1.07e10 J

Explanation:

The electric potential energy stored in a capacitor, expressed in terms of the value of the capacitance C, and the voltage between its terminals V, is as follows:

U =\frac{1}{2}*C*V^{2}

a) For the original capacitor, we can find directly U as follows:

U =\frac{1}{2}*1.81F*(73.9e3)^{2} V2 = 4.94e9 J  

U = 4.94*10⁹ J

b) Prior to find the electric potential energy of the upgraded capacitor, we need to find out the value of the capacitance C of this capacitor, which is identical to the original, except that has a different dielectric constant.

As the capacitance is proportional to the dielectric constant, we can write the following proportion:

ε₂ / ε₁ = \frac{943}{435}= \frac{C2}{C1} =\frac{Cx}{1.81F}

Cx =\frac{1.81F*943}{435} = 3.92 F

Once calculated the new value of the capacitance, as V remains the same, we can find the electric potential energy for the upgraded capacitor as follows:

U =\frac{1}{2}*3.92F*(73.9e3)^{2} V2 = 1.07e10 J

⇒ U = 1.07*10¹⁰ J

8 0
3 years ago
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