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3 years ago

B. Solve the following problem.

Physics

1 answer:

NemiM [27]3 years ago

4 0

Answer:

-2.83m/s^2

Explanation:

the object is decelerating because it's moving from 8.5 to rest (0)

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Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid

Korolek [52]

Answer:

$z= 2.5 \ m$

$z = (1 \ m , 4 \ m )$

Explanation:

From the question we are told that

Their distance apart is $d = 5.00 \ m$

The wavelength of each source wave $\lambda = 6.0 \ m$

Let the distance from source A where the construct interference occurred be z

Generally the path difference for constructive interference is

$z - (d-z) = m \lambda$

Now given that we are considering just the straight line (i.e points along the line connecting the two sources ) then the order of the maxima m = 0

$z - (5-z) = 0$

=> $2 z - 5 = 0$

=> $z= 2.5 \ m$

Generally the path difference for destructive interference is

$|z-(d-z)| = (2m + 1)\frac{\lambda}{2}$

=> $|2z - d |= (0 + 1)\frac{\lambda}{2}$

=> $|2z - d| =\frac{\lambda}{2}$

substituting values

$|2z - 5| =\frac{6}{2}$

=> $z = \frac{5 \pm 3}{2}$

$z = \frac{5 + 3}{2}$

$z = 4\ m$

and

$z = \frac{ 5 -3 }{2}$

=> $z = 1 \ m$

=> $z = (1 \ m , 4 \ m )$

7 0

3 years ago

Answer fast plz<br> ....................

luda_lava [24]

Answer:

114 m/s

Explanation:

see the image below

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3 years ago

A proposed ocean thermal-energy conversion (OTEC) system is a heat engine that would operate between warm water (25 degrees C) a

Sphinxa [80]

Answer:

$\eta=0.067$

Explanation:

Given that

Temperature of warm water ,T₁ = 25 °C

Temperature of cold water ,T₂ = 5 °C

The maximum possible efficiency of any heat is will be same as the efficiency of the Carnot heat engine.Therefore the maximum efficiency of OTEC system is given as follows

$\eta=1-\dfrac{T_2}{T_1}$

T should be Kelvin scale

Now by putting the values

$\eta =1-\dfrac{5+273}{25+273}$

$\eta=0.067$

Therefore the maximum efficiency will be 0.067 or 6.7%.

8 0

3 years ago

A pickup truck starts from rest and maintains a constant acceleration a0. After a time t0, the truck is moving with speed 25 m/s

MA_775_DIABLO [31]

Answer:

B v1= 12.5m/s

Explanation:

As the acceleration is constant and time taken is also same and distance covered is halfed so the speed will also be halfed.

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3 years ago

When considering special needs acceptance guidelines, which of the following is NOT included

Art [367]

What are the answer options? It says which of the following. :)

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3 years ago

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