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max2010maxim [7]
3 years ago
13

Observe some of the phenomena around your home. Look for something that you can’t explain right away, but that you could test wi

th an experiment. Then, design an experiment that you could conduct at home. Make sure to identify the independent, dependent, and controlled variables. You should also write your own hypothesis. You don’t need to perform the experiment, just identify the variables and write a hypothesis.
Physics
1 answer:
Leno4ka [110]3 years ago
3 0

a toy/model steam engine. how it works and how to measure horse power

You might be interested in
Light with a wavelength of 395 nm illuminates a metal cathode. The maximum kinetic energy of the emitted electrons is 0.76 eV .
lutik1710 [3]

Answer:

520.8 nm

Explanation:

We are given that

\lambda=395 nm=395\times 10^{-9} m

1 nm=10^{-9} m

Maximum kinetic energy,K_{max}=0.76 eV=0.76\times 1.6\times 10^{-19} V

1 e=1.6\times 10^{-19} C

We have to find the maximum wavelength of light.

We know that

h\nu=\frac{hc}{\lambda_0}+K_{max}

Where c=3\times 10^8 m/s

h=6.625\times 10^{-34}

6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}=\frac{6.625\times 10^{-34}\times 3\times 10^8}{\lambda_0}+0.76\times 1.6\times10^{-19}

6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}- 0.76\times 1.6\times10^{-19}=\frac{6.625\times 10^{-34}\times 3\times 10^8}{\lambda_0}

\lambda_0=\frac{6.625\times 10^{-34}\times 3\times 10^8}{6.625\times 10^{-34}\times \frac{3\times 10^8}{395\times 10^{-9}}- 0.76\times 1.6\times10^{-19}}

\lambda_0=5.208\times 10^{-7} m=520.8 nm

6 0
3 years ago
Select all that apply.
ryzh [129]

Answer:

All of above.

Explanation:

6 0
3 years ago
Find an expression for the electric field e⃗ at the center of the semicircle. hint: a small piece of arc length δs spans a small
ahrayia [7]
Let l = Q/L = linear charge density. The semi-circle has a length L which is half the circumference of the circle. So w can relate the radius of the circle to L by 

<span>C = 2L = 2*pi*R ---> R = L/pi </span>

<span>Now define the center of the semi-circle as the origin of coordinates and define a as the angle between R and the x-axis. </span>

<span>we can define a small charge dq as </span>

<span>dq = l*ds = l*R*da </span>

<span>So the electric field can be written as: </span>

<span>dE =kdq*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>

<span>dE = k*I*R*da*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>

<span>E = k*I*(sin(a)/R I_hat - cos(a)/R^2 j_hat) </span>

<span>E = pi*k*Q/L(sin(a)/L I_hat - cos(a)/L j_hat)</span>
8 0
3 years ago
Describe how work is done by a skater pulling in her arms during a spin. In particular, identify the force she exerts on each ar
liberstina [14]

Answer:

 ∑ τ =0,  L₀ = L_{f}

Explanation:

In a circular turning movement, when the arms are extended and then contracted in two possibilities:

- They are lowered the force of gravity is what pulls them, the tension of the muscle becomes zero to allow this movement.

    In this movement the force is vertical(gravity) and the movement of the center of mass of each arm is vertical, so that the work is the weight value of the arm by the distance traveled by the center of mass.

- Another possibility is that the arms have stuck to the body, in this case the person's muscles perform the force, this force is horizontal and the displacement is the horizontal of the center of mass of the arms from the extended position to the contracted

 

In these movements the torque of the external force is equal for each arm, but in the opposite direction, so they are canceled where a net torque of zero, this causes the angular momentum to be preserved, which changes is the moment of inertia of the system and therefore you must also change the angular velocity to keep your product constant

          ∑ τ =0

                L₀ = L_{f}

              I₀ w₀ = I w

4 0
3 years ago
When the distance increases, the electrostatic force____; we call this relationship proportional
Alik [6]

Answer:

I think decreases inversely

Explanation:

the third

5 0
2 years ago
Read 2 more answers
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