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insens350 [35]
4 years ago
11

The formula for całculating the number of calories burned while swimming at a moderate rate is C 2.9wt, where C represents the n

umber of calories burned, w represents your weight in pounds, and t represents the time you swim in hours. How could you use this formula to help you determine how long you should swim in order to burn a specific number of calories?
Mathematics
1 answer:
DaniilM [7]4 years ago
4 0
You would input your weight first then multiply 2.9 by your weight and put that as the denominator. For the numerator you would put how many colonies you want burnt. The answer to that is what you would put for t.
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Sunflower produce approximately 50 seeds per flower. If one ounce of sunflower seeds contain an average of 72 seeds, how many fl
ra1l [238]

Given :

Sunflower produce approximately 50 seeds per flower.

If one ounce of sunflower seeds contain an average of 72 seeds.

To Find :

How many flowers are needed to produce 2 pounds of seeds.

Solution :

1 pound = 16 ounces .

So , 2 pound = 32 ounces .

Number of seeds in 2 pounds of seeds, n = 32×72 = 2304 .

Number of flowers are :

N=\dfrac{2304}{50}=46.08

So , approximate number of flower required are 46.

Hence, this is the required solution.

5 0
4 years ago
Find the least common multiple of 12 and 18?
Evgesh-ka [11]
36 is the correct answer
8 0
3 years ago
Graph and label the image of the figure below after a dilation by a factor of 1/2.
neonofarm [45]
Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0
1 year ago
Please answer all please​
Firdavs [7]

Answer:

Step-by-step explanation:

The first parabola has vertex (-1, 0) and y-intercept (0, 1).

We plug these values into the given vertex form equation of a parabola:

y - k = a(x - h)^2 becomes

y - 0 = a(x + 1)^2

Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:

1 = a(0 + 1)^2, and from this we know that a = 1.  Thus, the equation of the first parabola is

y = (x + 1)^2

Second parabola:  We follow essentially the same approach.  Identify the vertex and the two horizontal intercepts.  They are:

vertex:  (1, 4)

x-intercepts:  (-1, 0) and (3, 0)

Subbing these values into y - k = a(x - h)^2, we obtain:

                                            0 - 4 = a(3 - 1)^2, or

                                                -4 = a(2)².  This yields a = -1.

Then the desired equation of the parabola is

y - 4 = -(x - 1)^2

7 0
3 years ago
A circle has a radius of 3. An arc in this circle has a central angle of 20°. What is the length of the arc? Either enter an exa
Semenov [28]

Answer:

\frac{\pi  }{3}

2 * \pi * 3  * \frac{20}{360}

120\pi/360 = \frac{\pi  }{3}

Step-by-step explanation:

5 0
3 years ago
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