1. let x = a number
x^2+5
2. let x = a number
2x-(x+19)
3. let x = a number
2x=1/3x + 9
4. let x = 1st integer
x+1 = 2nd integer
x+2 = 3rd integer
(x+x+1+x+2)/4
=(3x+3)/4
5. let x=smallest integer
x+1 = 2nd integer
x+2 = 3rd integer
x+3 = largest integer
x+x+1+x+2+x+3 = 9(x+3)
= 4x+6= 9x+27
Answer:
A.greater than 1
Step-by-step explanation:
1. take away all the symbols
2. 5-3
3.5-3=2
4. is 2 greater than 1
5. yes
6. answer is A.
Answe r .1875
Step-by-step explanation:
10/3 or 3 1/3
is the answer
Answer:
<u>the mean-average of the data without the outliers is 22572/94 = 240.12766 correct to four digits.</u>
Step-by-step explanation:
If the six outliers are removed, what is the mean average of the remaining data... is ASSUMED what the question was supposed to ask. I'll go out on a limb here, because there really isn't much else you can calculate with just
this much data anyways. I refer to the mean or average as the mean-average....just sayin'
Mean-Average = total/count , which means the total = count * mean-average.
Well, the data containing the outliers has a mean-average of 267 and a count of 100 statistics as given in the problem. So the total of all of the data including the outliers is 26700.
Likewise, the six outliers have a mean-average of 688 as given in the problem.
So the total of the outliers is 688 * 6 = 4128.
As a result, the total of the 94 statistics when the six outliers are rejected is 26700-4128=22572.
