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sladkih [1.3K]
3 years ago
10

What are the x and y intercepts of the graphed functionality ?

Mathematics
2 answers:
stiks02 [169]3 years ago
6 0

Answer:

X-intercepts: (1,0) and (-1, 0)

Y-intercept: (0,1)

Step-by-step explanation:

I believe the x-intercepts also have a multiplicity of 2 each if you need to know that.

a_sh-v [17]3 years ago
5 0

Answer:

Step-by-step explanation:

the x intercepts are -1 and 1 (where y = 0)

the y intercept is 1 (where x = 0)

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Exterior angles of a triangle. I need help on these.
ludmilkaskok [199]

Answer:

me no comprehendo te triangos

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
julsineya [31]

Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

D^{2} = (90 - x)^{2} + 90^{2}   (1)

\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}

2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}  

D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}   (2)

Since:

D = \sqrt{(90 -x)^{2} + 90^{2}}

When x = 45 (the batter is halfway to first base), D is:

D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

100.62 \frac{d(D)}{dt} = -(90 - 45)*31          

\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

D^{2} = 90^{2} + x^{2}  

\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}

D\frac{dD}{dt} = x\frac{dx}{dt}   (3)

We have that D is:

D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

4 0
2 years ago
Read 2 more answers
1/3 - 2/9 find the solution​
3241004551 [841]

Answer:

1/9

Step-by-step explanation:

1/3 - 2/9

Get a common denominator of 9

1/3 *3/3 = 3/9

3/9 - 2/9

1/9

4 0
3 years ago
I need help Im not too good Solving Problems Involving get Unig Rate.
ira [324]
To find unit rate, it's typically done with the equation (y/X). in this case X=minutes and y=laps. so plug the numbers into the equation.(81/27). whatever the answers is, that's your constant of proportionality, or unit rate. multiply your unit rate with the minutes and divide the laps by the unit rate to find the minutes.

minutes=m
laps=l
unit rate=k

m×k=l
l/k=m
3 0
3 years ago
What values of X make the two expressions below equal?
Mkey [24]

Answer:

A

Step-by-step explanation:

they dont come out the same

8 0
3 years ago
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