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galina1969 [7]
3 years ago
9

The perimeter of a triangle is 16 squar root 7 feet if two of the sides measure 343 square root feet amd 175 square root fins th

e length of the third side as a redo all in simplest form
Mathematics
1 answer:
yanalaym [24]3 years ago
7 0
The length of the third side is 4 7step-by-step the explanation- the perimeter of a triangle is 16 to the square root of 7 feet.
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Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25
sergey [27]

The first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

<h3>What are the coordinates of vertex for a quadratic function?</h3>

For a quadratic function of the form y = ax^2 + bx + c, its vertex form is obtained as:

y = ax^2 + bx + c\\y  =a(x^2 + bx/a) + c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2 -(b/2a)^2  )+ c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2) -a \times (b/2a)^2 + c\\\\y = a(x+b/2a)^2 - a \times (b/2a)^2 + c

For the form y = a(x-h)^2 + k, the vertex has coordinates (h, k)

Thus, for the obtained equation y = a(x+b/2a)^2 - a \times (b/2a)^2 + c, we get the coordinates of vertex as:

h = -b/2a, k = c - a\times(b/2a)^2

Thus, the coordinates of vertex of  y = ax^2 + bx + c is:

(h,k) = (-b/2a, c - a \times (b/2a)^2 )

The missing steps of work of Jan'ai are:

  1. Begin to write a function in factored form. f(x) = a(x+1)(x-5)
  2. Substitute x = 0, y = f(x) =  -25 to determine a. -25 = a(0+1)(0-5)
  3. Simplify and solve to find a. a=5
  4. Rewrite the function. f(x) = 5(x+1)(x-5)
  5. Rewrite in standard form. f(x) = 5x^2-20x-25
  6. Find the x-coordinate of the vertex. x = -20/2(5) = -20/10; x = -2
  7. Find the y-coordinate of the vertex.

y = 5x^2-20x-25

y = 5(-2)^2-20(-2)-25

y = 35

so (-2,35) is the coordinate of the vertex, which denotes the minimum.

So, as we see, in the 5th step, Jan'ai had the quadratic function f(x) = 5x^2-20x-25,

Comparing this to f(x) = ax^2 + bx + c, we get a = 5, b = -20, c = -25

The vertex's x-coordinate will be on -b/2a = -(-20)/ 2(5) = 20/10 = 2

But Jan'ai didn't putted that negative sign before b. in the 6th step.

Thus, the first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

Learn more about the vertex form of a quadratic equation here:

brainly.com/question/9912128

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