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zhuklara [117]
3 years ago
11

PLEASE HELP ME I HAVE BEEN TRYING TO DO THIS FOR HOURS!!

Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

99 (I am not sure if this is correct)

Step-by-step explanation

75/4.75 so we can see how many miles per mile and then we would round the answer we got would be 16 and then muiltiply by 6.25 and round it to the nearest mile so i got 99. (unless I missed calculated)

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What's the area of this rectangle?
Bess [88]

well, the assumption is that is a rectangle, namely it has two equal pairs, so we can just find the length of one of the pairs to get the dimensions.

hmmmm let's say let's get the length of the segment at (-1,-3), (1,3) for its length

and

the length of the segment at (-1, -3), (-4, -2) for its width

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{length}{L}=\sqrt{[1-(-1)]^2+[3-(-3)]^2}\implies L=\sqrt{(1+1)^2+(3+3)^2} \\\\\\ L=\sqrt{4+36}\implies L=\sqrt{40} \\\\[-0.35em] ~\dotfill

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{width}{w}=\sqrt{[-4-(-1)]^2+[-2-(-3)]^2}\implies w=\sqrt{(-4+1)^2+(-2+3)^2} \\\\\\ w=\sqrt{9+1}\implies w=\sqrt{10} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{A=Lw}\implies \sqrt{40}\cdot \sqrt{10}\implies \sqrt{400}\implies \boxed{20}

7 0
3 years ago
Given that √5 = 2.24 and √50= 7.07 , find <br> √500 and √0.5
sineoko [7]

Answer:

see explanation

Step-by-step explanation:

using the rules of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

\sqrt{\frac{a}{b} } ⇔ \frac{\sqrt{a} }{\sqrt{b} }

then

\sqrt{500}

= \sqrt{100(5)}

= \sqrt{100} × \sqrt{5}

= 10 × 2.24

= 22.4

-------------------------------

\sqrt{0.5}

= \sqrt{\frac{50}{100} }

= \frac{\sqrt{50} }{\sqrt{100} }

= \frac{\sqrt{50} }{10}

= \frac{7.07}{10}

= 0.707

3 0
2 years ago
scott is riding a bike course that is 50 miles long. So far, he has ridden 6 miles of the course. What percentage of the course
ad-work [718]

Scott has ridden 12% of the course.

Step-by-step explanation:

Length of bike course = 50 miles

Distance covered = 6 miles

Distance covered in percentage = \frac{Distance\ covered}{length\ of\ bike\ course}*100

Distance covered in percentage = \frac{6}{50}*100\\

Distance covered in percentage = \frac{600}{50}

Distance covered in percentage = 12%

Scott has ridden 12% of the course.

Keywords: percentage, distance

Learn more about percentages at:

  • brainly.com/question/4105480
  • brainly.com/question/4109519

#LearnwithBrainly

4 0
3 years ago
The radius of a garden in the shape of a regular pentagon is 18 feet. Find the area of the garden
bonufazy [111]
Think and do the math take your time

5 0
3 years ago
Question 15 of 26
DanielleElmas [232]

Answer:

3.5 yards

Step-by-step explanation:

3 0
3 years ago
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