Answer: angle 2 is supplementary to angle 1
ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.
<h3>What are Congruent Triangles?</h3>
Congruent triangles are triangles whose corresponding sides are congruent to each other.
The hypotenuse of triangle JKL(KL = 10) is congruent to a leg of triangle XYZ (YX = 10). This implies that they cannot be congruent triangles.
Therefore, ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.
Learn more about congruent triangles on:
brainly.com/question/11457412
Answer:
![59.19 ft^2](https://tex.z-dn.net/?f=59.19%20ft%5E2)
Step-by-step explanation:
step 1
Find the area of the circle
The area of the circle is equal to
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
we have
![r=7.2\ ft](https://tex.z-dn.net/?f=r%3D7.2%5C%20ft)
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
substitute
![A=(3.14)(7.2)^{2}](https://tex.z-dn.net/?f=A%3D%283.14%29%287.2%29%5E%7B2%7D)
![A=162.78\ ft^2](https://tex.z-dn.net/?f=A%3D162.78%5C%20ft%5E2)
step 2
we know that
The area of a circle subtends a central angle of 2π radians
so
using proportion
Find out the area of a sector with a central angle of 8 π/11 radians
![\frac{162.78}{2\pi }\frac{ft^2}{rad} =\frac{x}{(8\pi/11)}\frac{ft^2}{rad} \\\\x=162.78(8/11)/2\\\\x=59.19\ ft^2](https://tex.z-dn.net/?f=%5Cfrac%7B162.78%7D%7B2%5Cpi%20%7D%5Cfrac%7Bft%5E2%7D%7Brad%7D%20%3D%5Cfrac%7Bx%7D%7B%288%5Cpi%2F11%29%7D%5Cfrac%7Bft%5E2%7D%7Brad%7D%20%5C%5C%5C%5Cx%3D162.78%288%2F11%29%2F2%5C%5C%5C%5Cx%3D59.19%5C%20ft%5E2)
The answer is 1,1500 because you ha e to subtract the lowest to highest number