How do you divide 986 divided by 26 in partial quotients

What is a NON-EXAMPLE of a contant?

Vanyuwa [196]

A constant in algebra is a number on its own or a letter of the alphabet that can stand to represent a fixed number.

Step-by-step explanation:

For example ;

3x+5=11

in this equation

3 is the coefficient

x is a variable

+ is the operator

5 is a constant

11 is a constant

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A constant ;brainly.com/question/13225486

Keywords ; non-example, constant

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7 0

3 years ago

The angle \theta_1θ

enyata [817]

Answer:

$sin\theta_1 = \dfrac{\sqrt{217}}{19}$

Step-by-step explanation:

It is given that:

$cos\theta_1 = -\dfrac{12}{19}$

And we have to find the value of $sin\theta_1 = ?$

As per trigonometric identities, the relation between $sin\theta\ and \ cos\theta$ can represented as:

$sin^2\theta + cos^2\theta = 1$

Putting $\theta_1$ in place of $\theta$ Because we are given

$sin^2\theta_1 + cos^2\theta_1 = 1$

Putting value of cosine:

$cos\theta_1 = -\dfrac{12}{19}$

$sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}$

It is given that $\theta_1$ is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

$\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}$

8 0

3 years ago

a water tank holds 24,000 gallons. how many hours will it take for 2/3 of the water to be used if the water is used at an averag

Likurg_2 [28]

In the question, it is already mentioned that the water tank holds = 24,000 gallons
In the given question it is also mentioned that the need is to find the time required to use 2/3 of the total water that the tank holds.
So the need is to find the amount of water that equals 2/3 of the total water in the tank.
Then
Quantity of water that needed to be used = [24000 * (2/3)] gallons
= 16000 gallons
In the problem it is also mentioned that the average rate of consumption per day is 650 gallons.
So
650 gallons of water used in = 24 hours
16000 gallons of water will be used in = [(24/650) *16000] hours
= 590.77 hours
So the time required to consume 2/3 of the total water in the tank is 590.77 hours.

8 0

4 years ago

Plz help me just don't get it

fredd [130]

To make this problem easier you could make the denominators equal to combine the 2 bills to see how of his paycheck is being used already. to 2/7 = 6/21 and 1/3=7/21 so with 6/21 and 7/21 you can combine them and you have 13/21 is used on bills so 21/21(which represents the whole paycheck) - 13/21 =8/21 so 8/21 is what is left his paycheck to spend write this as a decimal by dividing and you will have the percentage that he has left so 8/21 = .38 so he can spend approximately 38% of his check on games and 63dollars * .38 is about 24dollars 63*.38 =24(approximately) you divide 8/21 and get an exact answer.

4 0

3 years ago

Read 2 more answers

Martey drew a model of the shool library

vova2212 [387]

Answer:

Q?

Step-by-step explanation:

3 0

3 years ago