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Marat540 [252]
3 years ago
11

Helllllllllppppppppp

Mathematics
1 answer:
Olin [163]3 years ago
6 0

Answer:

\frac{8}{5} x^{2}  - \frac{16}{5} xy + 4x

xy^{2} + \frac{2}{3}y - 8y^{2}z

Step-by-step explanation:

We have to simplify the followings:  

1) - \frac{4}{5}x (- 2x + 4y - 5)

= - \frac{4}{5}x \times (- 2x) +  - \frac{4}{5}x \times (4y) + - \frac{4}{5}x \times (- 5)  

{By distributive property of multiplication}

= \frac{8}{5} x^{2}  - \frac{16}{5} xy + 4x (Answer)

2) 2y^{2}( \frac{1}{2} x + \frac{2}{6}y - 4z)

= 2y^{2} \times (\frac{1}{2} x) + 2y^{2} \times ( \frac{2}{6}y) - 2y^{2} \times (4z)

{By distributive property of multiplication}

= xy^{2} + \frac{2}{3}y - 8y^{2}z (Answer)

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Choose one of the factors of x^3 + 343.
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First, note that 343=7^3. Then use the formula for the sum of perfect cubes:

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Therefore,

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