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bearhunter [10]
3 years ago
13

What is the area of triangle ABC in the image below?

Mathematics
1 answer:
babymother [125]3 years ago
7 0

Answer:

It's 31.5

Step-by-step explanation: The formula for right triangle is A=ab/2. A=area, a is one of the legs and b is the other leg. So you had for one leg 9 and for the other 7. You multiple 9 x 7 = 63. 63/2 = 31.5 for the area

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Organisers for a charity event sold 500 tickets. Adult price £3 and children £2. Money received from adult ticket sales is £400
Tatiana [17]

Answer: 280

<u>Step-by-step explanation:</u>

                  Quantity   X    Cost    =  Money Received

Adult:               x                   3                   3x          

Children:       500-x              2            2(500 - x) = 1000 - 2x


Adult = Children + 400

  3x   =  1000 - 2x + 400

  3x   =   1400 - 2x

  5x   =   1400

    x    =    280

7 0
3 years ago
Plzzzz helpppp asapppppp<br> **will mark brainliest **
neonofarm [45]

It's a 45-45-90 triangle,

where the legs are congruent, and the hypotenuse is sqrt(2) times the length of a leg.

6 0
3 years ago
Read 2 more answers
Graph the following Line:<br> 6x+3y=6
yulyashka [42]

Answer:

Visit geogebra.com

Step-by-step explanation:

none needed <3

8 0
3 years ago
Read 2 more answers
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
Suppose p(a) = 0.40 and p(a 
sveticcg [70]
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

P(A\cup B)+P(A\cap B)=P(A)+P(B)


For parts (a) and (b), you're given everything you need to determine P(B).

For part (c), if A and B are mutually exclusive, then P(A\cap B)=0, so P(A\cup B)=P(A)+P(B). If the given probability is P(A\cup B)=0.55, then you can find P(B)=0.15. But if this given probability is for the intersection, finding P(B) is impossible.


For part (d), if A and B are independent, then P(A\cap B)=P(A)\cdot P(B).
8 0
3 years ago
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