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Answer:
8.25 moles
Explanation:
Given parameters:
Number of moles of Al produced = 11 moles
Unknown:
Number of moles of oxygen produced = ?
Solution:
To solve this problem, we need to understand the problem.
The decomposition of an aluminium oxide must has produced oxygen and aluminium,
2Al₂O₃ → 4Al + 3O₂
now since the known is the oxygen gas; we can find the unknown aluminium:
3 mole of O₂ was produced with 4 mole of Al
x mole of O₂ will be produced with 11 moles of Al
x =
= 8.25 moles
Answer:
a. single replacement reaction
Explanation:
Mg(s) + 2HCl(aq)——-> H2(g) + MgCl2(aq)
Mg replaces H, so this is a single replacement reaction.
Answer:
4 mol of lithium nitride would be produced
Explanation:
6Li + N2 → 2Li3N
This equation means that 6 mol of lithium are reacted with 1 mol of nitrogen to make, 2 mol of lithium nitride.
So this is the rule of three to find out, how many moles of lithium nitride are been made, from 12 mol of Li.
6 Li _____ 2 Li3N
12 Li ________ (12. 2) / 6 = 4 moles
Molarmass of <span>Zn(C2H3O2)4 is 301.5561 g/mol
moles of </span>
<span>Zn(C2H3O2)4
= 62 g * 1 mol/(</span><span>301.5561 g) = 0.2056 mol
concentration = moles / volume
concentration * volume = moles
volume = moles / concentration
volume = 0.2056 mol / 1.5 M
volume = 0.13706 L
volume = 137 mL
volume = 140 mL
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