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vladimir1956 [14]

3 years ago

14

Where are electrons found in the atom?

1 answer:

RoseWind [281]3 years ago

5 0

In the electron shell

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At what height the acceleration due to gravity of the earth become half ?

Serggg [28]

Answer:

Acceleration due to gravity is reduced to half its value on the earth's surface at an altitude of 2.65×106 m

3 0

3 years ago

Compare the number of moles calculated in parts a) 0.03 and b). 0.064. Which of the three possible reactions discussed is consis

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Answer:don’t click link ur gonna get ur info taken

Explanation:

6 0

3 years ago

What are the simplest organic compounds called?

riadik2000 [5.3K]

<u>Answer:</u>

<u>Answer:hydrocarbons</u>

Explanation:

The simplest organic compounds are the hydrocarbons, which contain only carbon and hydrogen. Alkanes contain only carbon–hydrogen and carbon–carbon single bonds, alkenes contain at least one carbon–carbon double bond, and alkynes contain one or more carbon–carbon triple bonds.

4 0

3 years ago

The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea

Mariana [72]

Answer:

$\frac{1}{8}$

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

$\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}$

We can construct a table.

<u>No of half-lives</u> <u>Fraction remaining</u>

1 $\frac{1}{2}$

2 $\frac{1}{4}$

3 $\frac{1}{8}$

The general formula is

$\text{Fraction remaining} = \frac{1}{2^{n}}$

where <em>n</em> = the number of half-lives.

Thus, $\frac{1}{8}$ of the original carbon remains after 17 190 y.

8 0

3 years ago

This equation is not balanced. Click on the coefficient we should change first.<br> help ASAP

horrorfan [7]

Answer: The coefficient we should change first is for $NO_{3}$ .

Explanation:

The given reaction equation is as follows.

$Al + Ni(NO_{3})_{2} \rightarrow Al(NO_{3})_{3} + Ni$

Here, number of atoms present on reactant side are as follows.

Al = 1
Ni = 1
$NO_{3}$ = 2

Number of atoms present on the product side are as follows.

Al = 1
Ni = 1
$NO_{3}$ = 3

To balance this equation, multiply Al by 2 and $NO_{3}$ by 3 on reactant side. Also, multiply $Al(NO_{3})_{3}$ by 2 and Ni by 3 on the product side.

Hence, the equation can be rewritten as follows.

$2Al + 3Ni(NO_{3})_{2} \rightarrow 2Al(NO_{3})_{3} + 3Ni$

Now, number of atoms present on reactant side are as follows.

Al = 2
Ni = 3
$NO_{3}$ = 6

Number of atoms present on product side are as follows.

Al = 2
Ni = 3
$NO_{3}$ = 6

Since, the atoms on both reactant and product side are same. Hence, it is now a balanced chemical equation.

Thus, we can conclude that the coefficient we should change first is for $NO_{3}$ .

7 0

3 years ago