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3 years ago

Octane (C8H18) is a component of gasoline that burns

Chemistry

1 answer:

MatroZZZ [7]3 years ago

4 0

Answer:

hold on this will take me awhile

Explanation:

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How many atoms are in 2.75 moles of Mercury (Hg)?

lisov135 [29]

Answer:Imole H atoms have a mass of 1.007959. Example Problems: Use dimensional Analysis! 1. How many grams of carbon contain 2.0 moles of carbon atoms? 2.0 moles

Explanation:

6 0

2 years ago

A chemistry student needs 30.0 g of acetic acid for an experiment. He has available 1.2 kg of a 7.58% w/w solution of acetic aci

Tomtit [17]

Answer:

The mass of solution will be "395.78 g".

Explanation:

Given:

Mass of acetic acid,

= 30 g

Percentage,

= 7.58% w/w

Now,

⇒ % $=\frac{Mass \ of \ acetic \ acid}{Mass \ of \ solution}\times 100$

By putting the values, we get

⇒ $7.58=\frac{30}{Mass \ of \ solution}\times 100$

⇒ $Mass \ of \ solution=\frac{30\times 100}{7.58}$

⇒ $=\frac{3000}{7.58}$

⇒ $=395.78 \ g$

8 0

3 years ago

The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.

Vikki [24]

Answer : The solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

Solution : Given,

$K_{sp}=2.42\times 10^{-11}$

Molar mass of $MnCO_3$ = 114.945g/mole

The balanced equilibrium reaction is,

$MnCO_3\rightleftharpoons Mn^{2+}+CO^{2-}_3$

At equilibrium s s

The expression for solubility constant is,

$K_{sp}=[Mn^{2+}][CO^{2-}_3]$

Now put the given values in this expression, we get

$2.42\times 10^{-11}=(s)(s)\\2.42\times 10^{-11}=s^2\\s=0.4919\times 10^{-5}=4.919\times 10^{-6}moles/L$

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

$s=4.919\times 10^{-6}moles/L\times 114.945g/mole=565.414\times 10^{-6}g/L$

Therefore, the solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

8 0

2 years ago

What stops gravity from pulling water to the center of the earth

Alona [7]

Magnetism, or more specifically electromagnetic repulsion

4 0

3 years ago

Read 2 more answers

2NH.

liq [111]

Answer:

N=2

H=6

Explanation:

1.Balance a chemical equation in terms of moles.

2.Use the balanced equation to construct conversion factors in terms of moles.

3.Calculate moles of one substance from moles of another substance using a balanced chemical equation.

The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products.

(P.s it could also be where you have to solve it in which you have to simplify it first then solve it.) like adding them all up.

Hope this is the answer. :)

6 0

3 years ago