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3 years ago

Are starch molecules or glucose molecules bigger?

Chemistry

1 answer:

ale4655 [162]3 years ago

4 0

Answer: Starch

Explanation:

Why is starch larger than glucose? Based on the experiment, starch molecules are bigger in comparison to glucose molecules because they could not leave the tubing. This is supported by the presence of color change in the tubing for the starch test.

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Directions are in the picture

Mrrafil [7]

Answer:

Question Clear

Explanation:

Make sure your question is clear.

6 0

3 years ago

Sketch two amino acids side-by-side, on one of them label the functional groups, then show how the two can be joined together.

Alinara [238K]

Answer : The sketch of two amino acids side by side are shown below.

Explanation :

Amino acid : Amino acid are the acid that contains two functional groups which are carboxylic group, $-COOH$ and ammine group, $-NH_2$ .

When the two or more that two amino acids join together with the help of peptide bond, they produces polypeptide chain or protein.

The bond present between the two amino acid is called a peptide bond.

The peptide bond is a chemical bond that is formed between the two molecules when the nitrogen of one amino acid react with the carbon of another amino acid by releasing a water molecule.

Hence, the sketch of two amino acids side by side are shown below.

6 0

3 years ago

A particular uranium alloy has a density of 18.75 g/cm3.

soldi70 [24.7K]

I DONT KNOW THE ANSWER OF NO.B

SO SORRY FOR THAT!!!

5 0

3 years ago

What might happen if we heat the sphere

Reptile [31]

WE GONNA DIE RUNNNNNNNN

7 0

3 years ago

Write the balanced standard combustion reaction for the c5h7on3s2

AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0

3 years ago