Answer:
J is midpoint
side FJ = side JH Def of midpoint
angle GJF = GJH perpendicular bisector both 90 degrees
JG=JG reflexive property
Therefore triangle FJG = HJG
Answer:X/3X=3
We move all terms to the left:
X/3X-(3)=0
Domain of the equation: 3X!=0
X!=0/3
X!=0
X∈R
We multiply all the terms by the denominator
X-3*3X=0
Wy multiply elements
X-9X=0
We add all the numbers together, and all the variables
-8X=0
X=0/-8
X=0
Step-by-step explanation:
Answer:
tan(a) = -4/3
sec(a) = 5/3
Step-by-step explanation:
sine is opposite over hypotenuse. so no we have a triangle with a hypotenuse of 5 and an opposite side relative to some angle a of -4. the hypotenuse is never negative.
so draw a right triangle, mark one of the non right angles as a then the side opposite to that is -4 and the hypotenuse is 5. use the pythagorean theorem to find the remaining angle. The result could be positive or negative, but the questions specifically tells us we want the positive version.
b^2 + -4^2 = 5^2
b = 3
tangent is opposite over adjacent. for a we know the opposite is 3now so tan(a) = -4/3
Now, secant is 1/cos, so lets find cos(a)
cos is adjacent over hypotenuse, and we jsut found the adjacent is 3. so cos(a) = 3/5
Now 1/cos(a) = hypotenuse over adjacent so 5/3
Answer:
Step-by-step explanation:
Combine all like-terms to arrive at your answer:
Since 6 goes into both of them you would have to divide each by 6 to get 3/4. This is the answer. Hope this helped.
