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photoshop1234 [79]
4 years ago
14

Bharat and ingrid leave their building at the same time on their bikes and travel in opposite directions. If bharat's speed is 1

2 kilometers per hour and the Ingrid's speed is 14 kilometers per hour, how long will it take until they are 78 kilometers apart ?
Mathematics
1 answer:
yanalaym [24]4 years ago
6 0

Answer:

3 hours

Step-by-step explanation:

speed of Bharat = 12kilometers / hour

speed of Ingrid=14 kilometers / hour

For this problem we'll be using formula relating time, distance and speed.i.e

Distance = speed x time

Suppose Bharat is riding at a distance of 'b' kilometers, therefore time taken by him will be:

Time = distance/ speed

Time= b/12 hours.

Also, Ingrid can ride the distance at this time with speed of 14km/hr

The distance would be,

Distance = speed x time

Distance = 14 x (b/12) => 14b/12

Distance= 7b/6

Let 'd_{b}' be the distance that Bharat have covered after time 't'

therefore, d_{b} = 12 x t

Let 'd_{i} ' be the distance that Ingrid have covered after time 't'

therefore, d_{i} = 14 x t

In order to find the time when they are 78 kilometers apart, we will add d_{i}  and d_{b}, because they are travelling in opposite direction creating distance between them.

So,

d_{i} + d_{b} = 78

( 14 x t) + (12 x t) =78

14t + 12t =78

26t= 78

t= 78/26

t= 3hours.

thus, it will take 3 hours  until they are 78 kilometers apart

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