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Effectus [21]
3 years ago
5

2. Après avoir déterminé l'intervalle

Physics
1 answer:
SpyIntel [72]3 years ago
8 0

Answer:

i have no idea what this is

Explanation:

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The evidence is overwhelming that the Grand Canyon was dug over a span of millions of years by the erosive power of the Colorado
Vesna [10]

Answer:

evolutionary theory

Explanation:

The evidence is overwhelming that the Grand Canyon was dug over a span of millions of years by the erosive power of the Colorado River and that river’s tributary streams.

This evidence does not support catastrophic theory but it does support evolutionary theory, because it was gradual process and took place overtime. It did not happen in a catastrophic manner.

3 0
3 years ago
Which of the following could be cause of a irregular systolic reading
Paul [167]
Maybe number 4 could help.
3 0
3 years ago
Question 7 Points 2
uranmaximum [27]

Answer:

The dynamo has a wheel that touches the back tyre. As the bicycle moves, the wheel turns a magnet inside a coil. This induces enough electricity to run the bicycle's lights. The faster the bicycle moves, the greater the induced voltage - and the brighter the lights.

8 0
2 years ago
When the object is at half its amplitude from equilibrium, is the magnitude of its acceleration at half its maximum value?
Nezavi [6.7K]
We have F = kx or ma = kx where m and k are constants. Therefore, if x is halved, a must be halved too.
5 0
4 years ago
You are standing a distance of 17.0 meters from the center of a merry-go-round. The merry-go-round takes 9.50 seconds to go comp
GenaCL600 [577]

Answer:

(a)11.24 m/s

(b)7.44 m/s

(c)409 N

(d)539.55\mu

(e) 0

Explanation:

The period for 1 circle 2\pi of the merry go around is 9.5s. It means the angular speed is:

\omega = \theta / t = 2\pi / 9.5 \approx 0.661 rad/s

(a)The speed is

v = \omega * R = 0.661 * 17 = 11.24 m/s

(b) Centripetal acceleration:

a = \frac{v^2}{R} = \frac{11.24^2}{17} = 7.44 m/s^2

(c) Magnitude of the force that keeps you go around at this acceleration

F = ma = 55 * 7.44 = 409 N

(d) let the coefficient of friction by \mu. The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man

F_f = mg\mu = 55*9.81\mu = 539.55\mu

3 0
3 years ago
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