Suppose a large truck on a hydraulic lift exerts 7,000 N of force on a piston with an area of 0.4 m2. The piston can only suppor
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Answer:
3801.13 N
Explanation:
Pressure exerted on a surface is equivalent to applied force divided by the cross sectional area. Then, the applied force will be equal to the product of the pressure exerted and the cross sectional area.
Where given:
Atmospheric pressure (P1) = 1.013*10^5 Pa
T1 = 20+273.15 = 293.15 K
P2 = ?
T2 = 120+273.15 = 393.15 K
Using the gas equation: P1/T1 = P2/T2
Therefore, P2 = P1*T2/T1 = 1.013*10^5 *393.15/293.15 = 13.6*10^4 Pa
The net pressure = P2 - P1 = 13.6*10^4 - 1.013*10^5 = 34.6 kPa
The net force
Area = 0.11 m^2
Thus:
The net force = 3801.13 N
Answer:
The speed is maximum and the acceleration is zero
Explanation:
- The speed of the mass in simple harmonic motion can be found by using the law of conservation of energy. In fact, the total mechanical energy of the mass-spring system is sum of kinetic energy and elastic potential energy:
where
m is the mass
v is the speed
k is the spring constant
x is the displacement
As we can see, when the displacement is zero (x=0), the term representing the kinetic energy is maximum, so v (the speed) is also maximum.
- The acceleration of the mass in simple harmonic motion is proportional to the restoring force acting on the mass, which is given by Hook's law
where
k is the spring constant
x is the displacement
When x = 0, F = 0, so the net force acting on the mass is zero. Therefore, this also means that the acceleration of the mass is also zero: a = 0.