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Art [367]
3 years ago
14

Suppose a large truck on a hydraulic lift exerts 7,000 N of force on a piston with an area of 0.4 m2. The piston can only suppor

t 16,000 Pa of pressure. How much pressure is exerted by the truck on the piston?
Physics
1 answer:
uysha [10]3 years ago
7 0

Pressure is the amount of force per unit area. In formula it is,

P = F ÷ A

P = 7000 N ÷ 0.4 m2

P = 17,500 N/m2

The amount of pressure the truck exerts on the piston is 17,500 N/m2

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A larger impulse. A 1-kg ball has twice as much speed as a 10-kg ball.

Explanation:

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2 years ago
If your brakes give out, why can't you just pull the keys out of the ignition?
Pachacha [2.7K]

There should be a small amount of play in the wheel when the steering is locked. Gently pull the key from the ignition while you slowly jiggle the steering wheel back and forth. If this is the cause of the problem, the key should come out after a little effort.

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2 years ago
Two blocks are connected by a massless cable which goes through the center of a rotating turntable. The blocks have masses M1 =
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Answer:

If the final question is; at what velocity will the first block start to move outward in m/s?

v = 3.5596 \frac{m}{s}

Explanation:

The motion have the velocity that will make the block move using:

F_{1}*F_{r}+ F_{2}= Ec \\Ec= \frac{M*v^{2} }{r}

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Resolving:

\frac{m_{1}*v^{2}  }{r} = us*m_{1}* g + m_{2} * g

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v^{2} = 12.6714 \frac{m^{2} }{s^{2} }

v = 3.559 \frac{m}{s}

4 0
3 years ago
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AnnyKZ [126]

Answer:

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2 years ago
si tienes 2 circuitos uno en serie y otro en paralelo con el mismo valor en sus resistencias, para cuál circuito la resistencia
Novosadov [1.4K]

Answer:

circuito paralelo

Explanation:

Siempre el circuito en paralelo dara una resistencia menor. Recuerda que las resistencias se suman en el circuito en serie, an cambio en el circuito en paralelo, la corriente se bifurca de manera de circular con mayor intensidad por las ramas que tengan menos resistencia, y tal situacion llevara siempre a producir una menor resistencia equivalente.

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2 years ago
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