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vladimir2022 [97]
3 years ago
14

Two solid spheres, one of radius R and mass M, the other of radius 2R and mass 8M, roll down an incline. They start together fro

m rest at the top of the incline. Which one will reach the bottom of the incline first?
A) The small sphere
B) The large sphere
C) Depends on ramp length
D) Both reach the bottom together.
E) It depends on the height of the incline
Physics
1 answer:
sveta [45]3 years ago
7 0

Answer:

Explanation:

Given

mass of first sphere is M and radius R

Mass of other sphere is 8 M and radius 2 R

acceleration of a rolling body in an inclined plane is given by

a=\frac{g\sin \theta }{1+\frac{I}{mR^2}}

where I=moment of Inertia

m=mass of object

R=radius of object

\theta=inclination of plane

Moment of inertia of first body I=\frac{2}{5}MR^2

Moment of inertia other body I'=\frac{2}{5}(8M)(2R)^2=\frac{64}{5}MR^2

acceleration of first body a_1=\frac{g\sin \theta }{1+\frac{\frac{2}{5}MR^2}{MR^2}}

a_1=\frac{5}{7}g\sin \theta

acceleration of second body a_2=\frac{g\sin \theta }{1+\frac{\frac{64}{5}MR^2}{8M(2R)^2}}

a_2=\frac{g\sin \theta }{1+\frac{2}{5}}

a_2=\frac{5}{7}g\sin \theta

thus acceleration of first and second is same therefore they will reach at the same time                        

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