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Dima020 [189]
3 years ago
5

Find the area of the circle 57m use 3.14 for pi

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

A ≈ 10207.03

Step-by-step explanation:

Given: Radius = 57

To find: The area

Formula: A = \pi r^2

Solution: A = \pi r^2= \pi × 572 ≈ 10207.03453

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The equation would be

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astraxan [27]
The answer to f(x) 5x/2x-6 is 3
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3 years ago
A zoo has a black rhinoceros that weighs 18 times as much as an average-size chimpanzee. The rhinoceros weighs 2,250 pounds.
Vinvika [58]

Answer: 125 pounds

Step-by-step explanation:

Let's first represent the weight of the black rhinoceros and chimpanzee with variables. We will assign <em>r</em> for the rhinoceros and <em>c</em> for the chimpanzee.

In the question, we were given that the weight for a black rhinoceros is 18 times as much as an average-size chimpanzee. This makes 18 times the chimpanzee's weight equal to the rhinoceros' weight.

Let's put this into an equation.

r=18*c

Now, let's put in the values we know to find the weight of the chimpanzee (i.e., <em>c</em>). We know the weight of a rhinoceros (represented by <em>r</em>) is 2250 pounds, so we can replace it for <em>r</em> in the equation.

2250=18*c

To solve this equation, we can divide both sides by 18 to get c by itself and know what it's value is.

\frac{2250}{18}=\frac{18*c}{18}

We can remove the \frac{18}{18} from the right side to be left with c. We can also divide 2250 by 8 to get the weight of an average-size chimpanzee.

c=\frac{2250}{18}\\ c=125

Hence, an average-size chimpanzee weighs 125 pounds.

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2 years ago
The scale for a model is built to represent a real-life skyscraper. If a measurement of 4 cm on the model of the building is equ
Svetlanka [38]
The scale would be 1 centimeter: 9 meters
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